A uniform rod, shown in figure 1, is released from rest. It makes an initial angle of 0-40° above the horizontal. The end of the rod is connected to the inertial frame through a revolute joint. The revolute joint opposes the motion with a friction torque of T=12 Nm. The mass of the rod is M=4 kg and the length is L=2 m. A force F=20 N acts tangential to the direction of motion through the mass centre of the rod. Calculate the horizontal and vertical reactions at the pivot after the rod has passed through an angle of 180°, shown by the dotted line, and makes an angle 0=40° below the horizontal. L. Figure 1 Swinging rod

A uniform rod, shown in figure 1, is released from rest. It makes an initial angle of 0-40° above the horizontal. The end of the rod is connected to the inertial frame through a revolute joint. The revolute joint opposes the motion with a friction torque of T=12 Nm. The mass of the rod is M=4 kg and the length is L=2 m. A force F=20 N acts tangential to the direction of motion through the mass centre of the rod. Calculate the horizontal and vertical reactions at the pivot after the rod has passed through an angle of 180°, shown by the dotted line, and makes an angle 0=40° below the horizontal. L. Figure 1 Swinging rod

Classical Dynamics of Particles and Systems

5th Edition

ISBN:9780534408961

Author:Stephen T. Thornton, Jerry B. Marion

Publisher:Stephen T. Thornton, Jerry B. Marion

Chapter11: Dynamics Of Rigid Bodies

Section: Chapter Questions

Problem 11.10P

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