A uniformly graded dry sand specimen was tested in a resonant column device. The shear wave velocity υs determined by torsional vibration of the specimen was 220 m/s. The longitudinal wave velocity determined by using a similar specimen was 350 m/s. Determine each of the following: Poisson’s ratio, Modulus of elasticity (E) and shear modulus (G). Note: The void ratio and the specific gravity of soil solids of the specimen were 0.5 and 2.70, respectively.

Q: 14. A triaxial test is performed on a sample of unsaturated silt with a degree of saturation equal…

A: Effective Major Principal stress(σ1) = σd+σc-μ Effective Minor Principal stress(σ3)= σc-μ Where, σd…

Q: Following data are given for a direct shear test conducted on dry silty sand:Specimen dimensions:…

A: The given data is shown below:

Q: A sample of dry coarse sand is tested in the laboratory triaxial apparatus in. the undrained…

A: Data given,

Q: The results of a constant head permeability test for a fine sand sample having a diameter of 150 mm…

A:

Q: QUESTION # 1: Following data are given for a direct shear test conducted on dhy sand: • Specimen…

A:

Q: A soil sample has an internal friction 30°, it is subjected to axial principal effective stresses…

A: The shear parameters of the soil can be calculated by different methods such as  Direct shear test…

Q: During a constant head permeability test on a sand sample, 260 x 10^3 mm^3 of water were collected…

A: Given data: Volume of water collected: V=260×103 mm3  Time (t)= 2 minutes. Length of sample(L)=100…

Q: A direct shear test when conducted on a remolded sample of sand, gave the following observations at…

A: In direct shear stress Normal stress(P) and shear stress (S) are calculated at failure as P = normal…

Q: Three samples of soil are tested under consolidated undrained conditions with measurement of the…

A: Mohr circle is drawn to find the failure envelope and further the shear parameters of the soil. The…

Q: In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under…

A: confining pressure; σ3 = 50 kPa Deviator Stress; ∆σ = 150 kPa Now, we Know. Pressure applied; σ1 =…

Q: a deposit of normally consolidated dry sand a cone penetration test was conducted. Following are the…

A: Given Data: The dry unit weight of sand is, γsand=16 kN/m3   To Determine: The average peak friction…

Q: Q2. The following results were obtained at failure in a series of drained triaxial tests on fully…

A: Given: Results from drained triaxial test is given below Determine value of shear strength…

Q: A soil undergoes friaxial compression with a radial stress of 200 kPa and a deviator stress of 325…

A:

Q: uestion-2: In an Oedometer test on a 20 mm thick sample of saturated clay taken from a site, 50%…

A:

Q: Q # 4. The following are the results of four drained direct shear tests on undisturbed normally…

A: The given data is shown below: Diameter=50 mmHeight=25 mm

Q: Question attached

A: Standard Penetration Test is mostly used in geotechnical engineering to determine the relative…

Q: A cross-hole shear wave velocity test is carried out on a clay layer. The sensors are spaced 10 m,…

A: Spacing - 10m mean time - 0.003 sec γ=135 lb/ft3 PI - 26 Cu = 60 kPa

Q: By considering the failure surfaces in a vane shear test, show from the first principles that, for a…

A: Draw vane shear test apparatus and shear stress distribution:

Q: The P-wave velocity in a soil is 105 m/s. AssumingPoisson’s ratio to be 0.32, calculate the modulus…

A: P - Wave velocity = vp = 105 m/s   Unit weight of soil = γ = 18 KNm3   Poisson ratio = μ = 0.32

Q: The results of two drained triaxial tests on a saturated clay are as follows: chamber pressure…

A:

Q: A series of previous tests has established that the ultimate effective friction angle of a NC clayey…

A: Given Data: friction angle = 19.20 soil pressure = 105 kpa

Q: A cylindrical sample of soil having a cohesion of 80 kN/m2 and an angle of internal friction of…

A:

Q: In a pressuremeter test in a soft saturated clay, the mea- suring cell volume V, = 535 cm³, Po =…

A:

Q: Water flows through the constant head setup in the laboratory, as shown in the figure, where two…

A: The given data is: Pw=1000 kg/m3 volume of water=0.165/1000 m3 Q=0.165*10-3/(15*60)=1.83*10-7 m3/s

Q: The following are the results of four drained direct shear tests on undisturbed normally…

A: Shear stress is generally a force that leads to cause deformation of a material that is created…

Q: The following data are from a direct shear test on an undisturbed soil sample. Represent the data by…

A:

Q: Question Attached

A: The given data is shown below:

Q: In a drained triaxial compression test, a sample of sand fails at deviator stress of 150kPa under…

A:

Q: Question attached

A: Solution:

Q: HYDRAULIC CONDUCTIVITY PROBLEM 1: The results of a constant head permeability test for a fine sand…

A:

Q: For a dry sand specimen in a direct shear test box, the following are given: • Angle of friction:…

A: Angle of Friction (ϕ') = 38o Size of Specimen = 2x2x1.2 in Normal Stress (σ') = 20 lbin2

Q: A layer of soil profile in a tank with upward seepage is shown in Figure Q1. Calculate the total…

A:

Q: In a drained triaxial test on consolidated clay the stress and angle are as follows: Deviator stress…

A:

Q: 12.12 Following are the results of consolidated-undrained triaxial tests on undisturbed soils…

A: Given data  Consolidated undrained test Chamber pressure  Deviatric stress Pore water pressure…

Q: Three CU tri-axial tests were performed oa samples retrieved from a 4-meter-thick layer of saturated…

A: we know that for normally consolidated CU test cohesion will be zero, but here pore water pressure…

Q: The size of a sand specimen in a direct shear test was 50 mm x 50 mm x 30 mm (height). It is known…

A:

Q: (b) An oedometer test on a specimen of fully saturated stiff clay gave the following results in…

A: From the table calculate the thickness ; Thickness = initial thickness-change in thickness The…

Q: There is an upward flow of 0.06 ml/s through a sand sample with a coefficient of permeability 3 ×…

A:

Q: For clay specimens, drained direct shear tests were conducted and the following data were obtained.…

A: Draw the graph of normal stress versus shear stress as shown below and plot the line of failure…

Q: PROBLEM 2: During a constant-head permeability test on a sand sample, 260 x 10° mm of water were…

A:

Q: he angle of friction of a compacted dry sand is 37 degrees. In a direct shear test on the sand,…

A: The type of given soil is dry sandy soil.  The general property of dry sand is cohesion, C = 0 .…

Q: Q: The results of two drained triaxial tests on a saturated clay follow: Specimen I: 03=70 kN/m2…

A: Cohesion will be zero in drained saturated case.

Q: The results of a constant-head permeability test for a fine sand sample having a diameter of 70 mm…

A: Constant head test is used to find the permeability of the soil. This test is used for the…

Q: In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under…

A:

Q: A saturated specimen of cohesionless sand was tested under drained conditions in a triaxial…

A:

Q: A saturated specimen of cohesionless sand was tested under drained conditions in a triaxial…

A:

Q: Data and Results for Direct Shear Test: Normal Stress (kPa):  100; 200; 300 Shear Stress (kPa):…

A:

Q: 3. A dilatometer test was conducted in a clay deposit. The groundwater table was located at a depth…

A: Assume σ0 at a depth of 8m to be 95Kn/m2k0=Kd1.50.47-0.6  where k0=earth pressure at…

Q: In a slow triaxial test performed on a sand sample, the chamber pressure is 1.5 kg/cm^2 and the…

A: Given data  Chamber pressure (σ3) = 1.5 kg/cm2 Deviator stress (σd) = 4.5 kg/cm2

FEA for Dynamic Problems

Finite element analysis or FEA is a computational tool that evaluates the approximate solution for a particular engineering problem. The tools provided by FEA help to evaluate the solutions of partial differential equations (PDEs) computationally following a numerical approach. Solutions of the PDEs can also be performed by following traditional algebraic approaches, but when the problem gets towards the complex side, it becomes very tedious and almost impossible to arrive at the solutions. In such cases, the FEA fulfills the purpose by evaluating the equations following multiple time steps and iterations. The more the time steps and iterations, the more accurate the solution. The solution plotted by FEA analysis and mathematical approaches varies asymptotically.