Our system is using virtual memory and has 48-bit virtual address space and 32-bit physical address space. Page size is 8 KiB. (a) How many entries are needed for a single-level page table? What does the two-level page table look like if the part of the virtual address which identifies the page number is split into two fields, such that the second part has 3 bits more than the first part?
Q: the AMAT (in number of clock pulses)?
A: The AMAT (in number of clock pulses)
Q: Find the total bits required for given data size and calculate overhead in percentage: - How many…
A: Direct mapping is the simplest strategy, and it maps every block of memory space into only one…
Q: Consider a paging system with the page table stored in memory. a. If a memory reference takes 50…
A: The Answer is in step2
Q: 2. A system that uses a two-level page table has 212-byte pages and 32 -bit virtual addresses. The…
A: Given: -
Q: In an architecture with 18 bits of "virtual address" width, "page size" is given as 1024 bytes and…
A: We are given TLB as 2 -way set associative with 16 data blocks. # sets= data blocks/…
Q: A very old computer had 24-bit addresses and 4KB pages. How many virtual address bits were occupied…
A: Solution: Given, Virtual memory system = 24-bit Page size = 4 KB
Q: A computer with a 32-bit address uses a two-level page table. Virtual addresses are split into a…
A: The ask is to calculate the page size and numbr of pages in the address space for a computer with a…
Q: Question 1: a) Address translation is an important component in MMU. Let's consider a logical…
A:
Q: 1. Consider a 32bit address space with 2K bytes page size, assuming that each entry consists of 4…
A: Solution : Address Space consist of 32 bits, program size is 2^32 bytes i.e. 4GB. Page Size = 2K…
Q: a. Describe exactly how, in general, a virtual address generated by the CPU is trans- lated into a…
A: Answer: a) A Virtual address generated by the CPU is translated into physical main memory address by…
Q: Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB. Answer…
A: Here in this question we have given a 32 bit address system. Page size = 2KB. Virtual address =…
Q: A machine has 48-bit virtual addresses and 32-bit physical addresses. Pages are 8 KB. How many…
A: Actually, given information: A machine has 48-bit virtual addresses 32-bit physical addresses.
Q: a simple paging system with 224 bytes of physical memory, 256 pages of logical address space, and a…
A: Given : Physical memory = 224 bytes Logical address space = 256 pages Page size = 210 bytes
Q: Consider the virtual memory scheme using paging. The page size is 128 bytes. The entries in the page…
A: In this case, the machine is a 16-bit system with a 4KB page size and 64KB of physical memory.…
Q: 5. Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses. a) What is the…
A: A virtual address space or address space is the set of ranges of virtual addresses that an operating…
Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
A: A cache is an equipment or programming segment that stores information so future solicitations for…
Q: 9. Consider a system that uses 32-bit addresses and page table structures as discussed in class. If…
A: 32 bits= 2^5 256 pages= 2^8
Q: For a system employing paging, consider a logical address space of 1024 pages of 4096 bytes, mapping…
A: Here we have to find but used for logical address space(LAS)..LAS is consist of two parts page no…
Q: Consider a system with 256Mbytes of main memory with page ize of 4Kbytes. It has a logical address…
A: Here in this question we have given main memory size= 256MB. Page size = 4KB Logical address space=…
Q: (a) Explain the use of TLBs to improve paging efficiency. (b) Consider a paging system with the…
A: A). To overcome this problem a high-speed cache is set up for page table entries called a…
Q: Consider a 48-bit virtual address space. The system hierarchical paging. Therefore, the page table…
A: 1)P1 x 1 15/16" 3)8-bit
Q: Question 12 Suppose you have a byte-addressable virtual address memory system with 8 virtual…
A: The solution for the above given question is given below:
Q: A computer has 32-bit virtual addresses and the page size is 2^9 KB. Suppose the text, data, and…
A: Here the virtual address size is 32 bits. Page size is 29 Bytes. Two level page table.
Q: a) In the SRAM region, what is the corresponding bit-band alias address for the bit [4] of the…
A: #define BITBAND_SRAM_REF 0x20000008 #define BITBAND_SRAM_BASE 0x22000008 #define BITBAND_SRAM(a,b)…
Q: (b) Consider a paging system with the page table stored in memory. If a memory reference takes 200…
A: Ans:- a) If memory access takes 200 nanoseconds, how long does a paged memory reference take?200…
Q: Suppose we have a byte-addressable computer using fully associative o 20-bit main memory addresses…
A: Actually, 1 byte =8 bits. cache memory is a fast access memory.
Q: 1. Write about the entire details of memory structure design and characteristics. 2. How much the…
A: answer is given below:-
Q: The PowerPC uses a hardware managed TLB with an inverted page table. Discuss its advantages and…
A: Given: The PowerPC uses a hardware managed TLB with an inverted page table. Discuss its advantages…
Q: Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main…
A: Answer: Firstly a little explanation about cache , cache lines and k way associative mapping. A…
Q: A virtual address of 32 bits is passed on to the TLB. If the number of entries (number of cache…
A: Please upvote. I am providing you the correct answer below. please. For solving this question we…
Q: Suppose a computer using direct-mapped cache has 2 bytes of byte-addressable main memory and a cache…
A: Given: The computer is using direct-mapped cache. Size of the main memory = 220 bytes Size of the…
Q: Consider a system with 36-bit addresses that employs both segmentation and paging. Assume each PTE…
A: This is Operating system related question.
Q: If a system has a 4-MB address space, where each page is 4 KB, and page table accesses take 100 nS,…
A: Given Data : Size of Address Space = 4 MB Size of the page = 4 KB One page tablet/page access…
Q: Consider a paging system with the page table stored in memory. a. If a memory reference takes 400…
A: Since, number of memory accesses required by a paged memory reference = 2 Time taken by a memory…
Q: Suppose we have a virtual address of 26 bits in a byte addressable machine. Page size is 8K bytes.…
A: Suppose we have a virtual address of 26 bits in a byte addressable machine. Page size is 8K bytes.…
Q: a) A paging system with 512 pages of logical address space, a page size of 2* and number of frames…
A:
Q: Consider a word addressable system. The main memory is of size 2 MB and direct-mapped cache…
A: consider word addressable system. The main memory size of 2MB and direct -mapped cache containing…
Q: Consider a paged virtual memory system with 12 bit virtual addresses & IKB pages Each page table…
A: The answer for number of levels page tables are
Q: Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB, and a PTE…
A: Data given in the question, 32-bit address system page size of 2 KB PTE (Page Table Entry) size of 1…
Q: Consider a computer system with a 32-bit logical address and 4-KB page size. The system supports up…
A: A) Number of entries in conventional single level page table = number of pages in virtual address =…
Q: Ql(a). Consider a logical address space of 64 pages with 1-KB frame size mapped onto a physical…
A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: Consider a computer system with a 64-bit logical address and 32-KB page size. The system supports up…
A: 2) Consider a computer system with a 64-bit logical address space and 2-KiB page size. The system…
Q: Consider a system with 64-bit address that supports multi-level page tables with two levels. The…
A: The address of a process is first divided into equal-sized pages. These pages are kept under a table…
Q: QUESTION 2 Suppose a computer using direct mapped cache is using 216 (64K) bytes of byte-addressable…
A: Here, we are given a direct mapped cache and main memory size with cache size and cache block size.…
Q: A system that uses a two-level page table has 212 bytes pages and 32-bit virtual addresses. Assume…
A: Data given, 2^12 bytes pages 32-bit virtual addresses 4-byte each entry 10 bits of address serve as…
Q: How many entries are needed in the inner page tables
A: Page table is used by the virtual memory system to store the mapping between logical address and…
Q: a) In the SRAM region, what is the corresponding bit-band alias address for the bit [4] of the…
A: a) In the SRAM region, what is the corresponding bit-band alias address for the bit [4] of the…
Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
A: Introduction of Cache Mapping: A cache is the fastest memory and used to increase the speed of the…
oprating system
Step by step
Solved in 2 steps
- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses.(a) What is the main advantage of a multilevel page table over a single-level one?(b) With a two-level page table, 16-KB pages, and 4-byte entries, how many bits should be allocated for the top-level page table field and how many for the next-level page table field? Explain.On a simple paging system with 224 bytes of physical memory, 256 pages of logical address space, and a page size of 210 bytes. 1. How many bits are needed to store an entry in the page table (how wide is the page table)? Assume a valid/invalid 1-bit is included in each entry. 2. If the page table is stored in the main memory with 250nsec access time, how long does a paged memory reference take? 3. If the page table is implemented using associative registers that takes 95nsec. and main memory that takes 200nsec, what is the total access time if 75% of all memory references find their entries in the associative registers?
- Suppose that a machine has 42-bit virtual addresses and 32-bit physical addresses.{a} How much RAM can the machine support (each byte of RAM must be addressable)?{b} What is the largest virtual address space that can be supported for a process?{c} If pages are 2 KB, how many entries must be in a single-level page table?{d} If pages are 2 KB and we have a two-level page table where the first level is indexed by 15-bits, then how many entries does the first-level page table have?{e} With the same setup as part {d}, how many entries are in each second-level page table?{f} What is the advantage of using a two-level page table over single-level page table?(b) Consider a paging system with the page table stored in memory. If a memory referencetakes 200 nano seconds, how long does a paged memory reference take? If we add a TLB,and 75% of all page references are found in the TLB, what is the effective memory referencetime? (Assume that it takes zero time to find an entry in the TLB if it is already present).Consider a computer which uses virtual addressing with 32 bit addresses and a two level page table. The virtual addresses are split into a 9 bit top level page table field, an 11 bit second level page table field and an offset. How large are the pages and, how many are there in the address space?
- Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB, and a PTE (Page Table Entry) size of 1 B. Answer the following questions, assuming a virtual address 0x00030f40 a. What is the virtual page number (VPN) and the offset in binary for the given virtual address? b. How many virtual pages are there in the system?Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB. Answer the following questions, assuming a virtual address 0x00030f40 A. What is the virtual page number (VPN) and the offset in binary for the given virtual address? B. How many virtual pages are there in the system?A computer with a 32-bit address uses a two-level page table. Virtual addresses are split into a 9-bit top-level page table field, an 11-bit second-level page table field, and an offset. How large are the pages and how many are there in the address space?
- Suppose a computer using direct mapped cache has 4G Bytes of main memory and a cache of 256 Blocks, where each cache Block has 16 Words, and Word Size is 4 Bytes. a)How many blocks of main memory? b)What is the format of a memory address as seen by the cache (Tag, Block and Word fields)? c)To which cache block will the memory reference 0000146A in Hex?4. Given that the main memory size is 32KB, the page size is 64B, the word size is 1B, and n-level paging is applied. What is the page number size? If (5, 10) is a record in the outer page table stored in PCB and (9, 7) is a record in the inter page table stored in page frame No.10, what is the physical address of the logical address 0010101001000110 in HEX?Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory of 64 frames. a. How many bits are required in the logical address? b. How many bits are required in the physical address?