Consider a logical address space of 64 pages with 2048 words per page; mapped onto a physical memory of 32 frames a. How many bits are required in the logical address? [1 Mark] b. How many bits are required in the physical address? [1 Mark] c. How many entries are there in single-level page table? [0.75 Mark]
Q: Given a 32-bit virtual address space and a 24-bit physical address, determine the number of bits in…
A: As given a 32-bit virtual address space and a 24-bit physical address, determination the number of…
Q: Consider a logical address space of 16 pages of 8192 words each, mapped onto a physical memory of…
A: Logical memory has 16 pages and each of those pages has 8192 words. In order to address every one of…
Q: Consider a logical address space of 8 pages of 1024 words each, mapped into a physical memory of 32…
A: The correct answer is option d) 13 bits and 15 bits Explanation: Physical Memory = 32 frames = 2^5…
Q: Consider a logical address space of 8 pages of 1024 words mapped into memory of 32 frames. How many…
A: Introduction :Given , Logical address space = 8 pages size of a page = 1024 wordsmemory size = 32…
Q: Consider the following page table in a demand paging system. Assume the page size of 256 bytes.…
A: using demand paging system assume the page size of 256 bytes.
Q: multi-level paging used by a process that has following: a. Logical Address = 64 bits b. Page size…
A: A. Logical address bits is 64 So logical address space is 264 B B. One page table entry size = 4B…
Q: Consider a logical address with a page size of 16 KB. How many bits must be used to represent the…
A: The number of bits required to store the page offset in the logical address is 14. Therefore, the…
Q: Given that the main memory size is 32KB, the page size is 64B, the word size is 1B, and n-level…
A:
Q: Consider a logical address of 128 pages of 1024 words each, mapped onto a physical memory of 64…
A: The Logical address will have 17 bits and the phycial address will have 16 bits. Explaination :…
Q: Give the number of the virtual page that the byte with virtual memory address 52000 belongs to,…
A: Page size = 8KiB This means page offset = log 8KiB = 13 bits So the least significant 13 bits will…
Q: Consider a system with 39-bit virtual addresses, 44-bit physical addresses, 4096 byte pages, and the…
A: The answer is
Q: Given a 32-bit virtual address space and a 24-bit physical address, determine the number of bits in…
A: please check further steps for answer :
Q: Consider a logical address space of eight pages of 1024 words ach, mapped on to a physical memory of…
A: ANSWER:-
Q: a) A paging system with 512 pages of logical address space, a page size of 2³ and number of frames…
A: Here in this question we have given Page size = 256 No of frame = 1024 Page in logical address=…
Q: 2. Consider the following assumptions: Size of virtual address: 64 bits Size of physical address: 29…
A: Find the required answer with calculation given as below :
Q: 5. Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses. a) What is the…
A: A virtual address space or address space is the set of ranges of virtual addresses that an operating…
Q: Consider a system with N bytes of physical RAM, and M bytes of virtual address and frames are K…
A: Here the virtual memory size = M bytes And page size is K bytes. The virtual address is divided…
Q: For a system employing paging, consider a logical address space of 1024 pages of 4096 bytes, mapping…
A: Here we have to find but used for logical address space(LAS)..LAS is consist of two parts page no…
Q: Assuming a page size of 4 Kbytes and that a page table entry takes 4 bytes, how many levels of page…
A:
Q: Consider a 48-bit virtual address space. The system hierarchical paging. Therefore, the page table…
A: 1)P1 x 1 15/16" 3)8-bit
Q: Assume a 32-bit virtual address and 4 MBs of memory (i.e., DRAM). If the page size is 1 KB, then…
A: Assume a 32-bit virtual address and 4 MBs of memory (i.e., DRAM). If the page size is 1 KB, then…
Q: Consider a system that has 4K pages of 512 bytes in size in thể logical address space. The physical…
A: The Answer is Given data Number of pages = 4k page size ps = 512 B = 2^9 B
Q: 1. Consider a logical address of 128 pages of 1024 words each, mapped onto a physical memory of 64…
A: The answer as given below:
Q: 6. Consider a logical address space of 16 pages of 2048 words each, mapped onto a physical memory of…
A: Given that, Logical address of 16 pages of 2048 words each. Number of physical memory frames= 4
Q: Consider a logical address space of 512 pages with a 4-KB page size, mapped onto a physical memory…
A:
Q: Logical Address = 4 GB, Physical Address PA= 64 MB, Page Size = 4 KB, then calculate Number of…
A: Logical Address = 4 GB, Physical Address PA= 64 MB, Page Size = 4 KB, then Number of pages =…
Q: Consider a logical address space of 1K pages with a 4KB page size, mapped onto a physical memory of…
A: Below is the answer to above question. I hope this will be helpful for you..
Q: Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory…
A: According to the Question below the Solution:
Q: Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory…
A: a. Logical address space (/size) = 2mLogical address space (/size) = number of pages × page…
Q: Consider a logical address space of 32 pages with 1,024 words per page, mapped onto a physical…
A: As mentioned in the question above, addressing is done with 1024 words per page, 1024 = 210 , 1024…
Q: a) A paging system with 512 pages of logical address space, a page size of 2* and number of frames…
A:
Q: Consider a system that has a 20-bit virtual address, a 16-bit physical address, and a 4-KB page…
A:
Q: Our system is using virtual memory and has 48-bit virtual address space and 32-bit physical address…
A: A. Page size = 8KiB So page offset bits = 13 bits Total # of page table entries required = total…
Q: Q3: If page in logical address space consists of 32 words. And the size of that address is 12 bits,…
A:
Q: Suppose you have a byte-addressable virtual address me system with 8 virtual pages of 64 bytes each,…
A: Solution: Considering that it is be available 64byte = 8 pages contains so, TNB(total number of bits…
Q: Consider a logical address space of 1024 pages with 2 KB page size, mapped onto a physical memory of…
A: As given, we need to find out, how many bits are required in the logical address. Given data -…
Q: A paging system has the following parameters 8GB of physical memory, page size of 4KB; 2 pages in…
A: Let's understand step by step : Given , Physical Address Space (Physical memory) = 8 GB…
Q: Given a virtual memory of size 4 GiB, physical memory of size 512 KiB, and page size equal to 4 KiB.…
A: Ans:) The higher order bits of any virtual address creates a page number while lower order bits form…
Q: Consider a computer system with a 32-bit logical address and 4-KB page size. The system supports up…
A: A) Number of entries in conventional single level page table = number of pages in virtual address =…
Q: Given a virtual memory of size 4 GiB, physical memory of size 1 GiB, and page size equal to 256 KiB.…
A: Here in this question we have given Virtual memory size = 4GiB Physical memory size = 1GiB Page size…
Q: Ql(a). Consider a logical address space of 64 pages with 1-KB frame size mapped onto a physical…
A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: Suppose we have a byte-addressable computer using a direct mapped caching with 20-bit main memory…
A: Actually, binary numbers are 1's and 0's. 1 byte =8 bits
Q: Consider a system with 64-bit address that supports multi-level page tables with two levels. The…
A: The address of a process is first divided into equal-sized pages. These pages are kept under a table…
Q: Assume a logical address space consists of 4 pages of 4096 words each and is mapped to a physical…
A: logical address space consists of 4 pages of 4096 words 256 frames
Q: Take a look at a 64-bit logical address space. a. Assuming a page size of 4 KB Discover the truth.…
A: Introduction: the question is about Take a look at a 64-bit logical address space. a. Assuming a…
Q: Given a modern 64-bit architecture with 6-bytes used for each page pointer, 1 MB pages, and 16 GB…
A: We have given that a modern 64-bit architecture with 6-bytes used for each page pointer, 1 MB…
Q: Consider a logical address space of 8 pages of 1024 words each, mapped int a physical memory of 32…
A: Consider a logical address space of 8 pages of 1024 words mapped into memory of 32 frames. How many…
Q: Consider a computer system with a 30-bit logical address and 4-KB page size. The system supports up…
A: 1.
Q: Consider a logical address space of 1024 pages of 2048 words each, mapped onto a physical memory of…
A: Question :-
Q: On a simple paging system with 224 bytes of physical memory, 256 pages of logical address space, and…
A: Here, we are given physical memory size , pages in logical address space, page size and asked the…
need answer on all questions, a, b, and c
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- Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory of 64 frames. a. How many bits are required in the logical address? b. How many bits are required in the physical address?Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory of 64 frames. (book: 8.23) How many bits are required in the logical address? How many bits are required in the physical address?Consider a logical address space of 512 pages with a 2-KB page size, mapped onto a physical memory of 64 frames. How many bits are required in the logical address?
- Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses.(a) What is the main advantage of a multilevel page table over a single-level one?(b) With a two-level page table, 16-KB pages, and 4-byte entries, how many bits should be allocated for the top-level page table field and how many for the next-level page table field? Explain.Suppose that a machine has 42-bit virtual addresses and 32-bit physical addresses.{a} How much RAM can the machine support (each byte of RAM must be addressable)?{b} What is the largest virtual address space that can be supported for a process?{c} If pages are 2 KB, how many entries must be in a single-level page table?{d} If pages are 2 KB and we have a two-level page table where the first level is indexed by 15-bits, then how many entries does the first-level page table have?{e} With the same setup as part {d}, how many entries are in each second-level page table?{f} What is the advantage of using a two-level page table over single-level page table?Consider a logical address space of 32 pages of 1024 words each, mapped onto a physical memory of 8 frames. How many bits are there in logical address and how many bits are there in physical address?
- Consider a logical address space of 1024 pages with 2 KB page size, mapped onto a physical memory of 128 frames. How many bits are required in the logical address? Select one: a.512 bits b.10 bits c.18 bits d.21 bitsIf we assume each page is 4Kbyte (2^12), for 832 bit system with the 4-GB (2^32) virtual address, space, how many page table entries each page table must have. A. 2^21 B. 2^18 C. 2^19 D. 2^20Consider a logical address space of 1024 pages with 2 KB page size, mapped onto a physical memory of 128 frames. How many bits are required in the physical address? Select one: a.56 bits b.18 bits c.7 bits d.21 bits
- Suppose you have a byte-addressable virtual address memory system with 16 virtual pages of 64 bytes each and 4-page frames. Assuming the following page table, answer the questions below: Page # Frame # Valid bit 0 2 1 1 3 1 2 - 0 3 0 0 4 1 1 5 - 0 6 - 0 7 - 0 A. What physical address corresponds to the virtual address 0x42? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper explanation) B. What physical address corresponds to the virtual address 0x72? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper explanation) C. What physical address corresponds to the virtual address 0x84? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper explanation)Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB, and a PTE (Page Table Entry) size of 1 B. Answer the following questions, assuming a virtual address 0x00030f40 a. What is the virtual page number (VPN) and the offset in binary for the given virtual address? b. How many virtual pages are there in the system?Suppose you have a byte-addressable virtual address memory system with 16 virtual pages of 64 bytes each and 4-page frames. Assuming the following page table, answer the questions below: Page # Frame # Valid bit 0 2 1 1 3 1 2 - 0 3 0 0 4 1 1 5 - 0 6 - 0 7 - 0 a) Show the virtual address format, including the name and size of the fields. b) Show the physical address format, including the name and size of the fields. c) What physical address corresponds to the virtual address 0x00? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper explanation) d) What physical address corresponds to the virtual address 0x42? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper explanation) e) What physical address corresponds to the virtual address 0x72? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page…