A viral video featured a football quarterback running into the backside of one of his offensive linemen, falling to the ground, and dropping the football, causing the opposing team to pick up the ball and score a touchdown. In a survey of 405 people, 352 reported having seen the video. Create a 95% confidence interval for the proportion of people who have seen the video. Use a TI-83, TI-83 plusror TI-84 calculator, rounding your answers to three decimal places. Provide your answer below: OD)

Q: Identify the t -scores for a 90% confidence interval if the sample size is 25?

A: Givensample size(z)=25α=1-0.90=0.10α2=0.05

Q: In a recent poll, 300 people were asked if they liked dogs, and 54% said they did. Find the Margin…

A: Obtain the margin of error for the poll at the 95% confidence level. The margin of error for the…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Sample size:The minimum sample size for a desired confidence level, α with a given margin of error,…

Q: In a random sample of 145 UNO students, we find that 53% have attended a Maverick hockey game at…

A:

Q: In a recent poll, 340 people were asked if they liked dogs, and 31% said they did. Find the margin…

A:

Q: 3. Cyber Monday Shopping A survey of 1000 U.S. adults found that 33% of people said that they would…

A: It is given that Sample size n = 1000 Sample proportion = 33% = 0.33 The critical value of t at 95%…

Q: In a recent poll, 240 people were asked if they liked dogs, and 46% said they did. Find the Margin…

A: Given that, Critical values: By using the standard normal table of Z, the critical value at 95%…

Q: We would like to know: "What percentage of college students read the college newspaper every day?"…

A: It is provided that there is random sample of 500 college students in which 231 students said that…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A:

Q: In a recent poll, 560 people were asked if they liked dogs, and 22% said they did. Find the margin…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A:

Q: In a recent poll, 500 people were asked if they liked dogs, and 54% said they did. Find the margin…

A: Here we need to find the Margin of error corresponding to 95% confidence level.

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A:

Q: A health insurance firm wants to estimate the proportion of a population that would receive the flu…

A:

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Solution:There is no estimates available, hence the sample proportion is assumed to be 0.50.The…

Q: 1. A poll of 2,500 people shows that 50% approve of a smoking ban in bars and restaurants. What is…

A:

Q: In a recent poll, 240 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: In a recent polI, 200 people were asked if they liked dogs, and 15% said they did. Find the margin…

A: From the provided information, Sample size (n) = 200 15% people said they like dogs that is p̂ =…

Q: The Pew Social Media Update 2014 surveyed 1,597 adult internet users on which social media websites…

A: Number of users (n) = 1597 Number of  users who use Facebook (x) = 1134 Find the sample proportion:…

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: In a recent poll, 260 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: In general, when you increase the confidence level for a confidence interval using the same sample…

A: As confidence level increases critical value is going to increase .  Here they given sample…

Q: According to a poll taken in a certain​ country, when adults were asked whether they were​ thriving,…

A: Given,n = 440x = 193a) Sample proportion p^ = xn    p^ = 193440 = 0.4386 b)np^ = 440 x 0.4386 =…

Q: A research institute poll asked respondents if they felt vulnerable to identify a theft. In the poll…

A: Given,n=1000x=501p^=xnp^=5011000=0.5011-p^=1-0.501=0.499α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a recent poll, 170 people were asked if they liked dogs, and 24% said they did. Find the margin…

A:

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: A Pew Research Center survey of 1,857 internet users found that 1,124 people agreed that online…

A: Given: CI=95% p^=11241875=0.599 n=1875

Q: In a random sample of 200 people, 154 said they watched educational television. We wish to construct…

A: Given there are 200 people, 154 said they watched educational television. a) Given confidence…

Q: In June 2020, a Gallup Poll asked U.S. adults whether immigration was a good thing or a bad thing…

A: Given : n = 1000 X = 600

Q: In a recent poll, 450 people were asked if they liked dogs, and 54% said they did. Find the Margin…

A: Solution

Q: A philanthropic organization sent free mailing labels and greeting cards to a random sample of…

A:

Q: In a recent poll, 150 people were asked if they liked olives, and 23% said they did. Find the margin…

A: Given: n=150 p=0.23 α=0.1

Q: In a recent poll, 600 people were asked if they liked dogs, and 33% said they did. Find the Margin…

A: Margin of error (M.E.): The margin of error for proportion p is given by,

Q: A random sample of accountants were asked whether they double-check their calculations on a tax…

A: Here the sample proportion is given by, p^ Therefore α level confidence interval is given by, p^ -…

Q: In a recent poll of 200 randomly selected adults in the U.S., 130 were registered to vote. a) What…

A: Hello, thanks for your question. Since you have posted a question with multiple sub-parts, we will…

Q: in a recent survey of 1000 adults ages 18 to 40, 34% said they had no credit cards. find the 95%…

A: The sample size n=1000. The sample proportion is 0.34. The confidence level is 95%. The area between…

Q: A website for car reviewssurveyeda random sample of 102car owners, and21wished they would have…

A:

Q: Which of the below is the correct calculation of the 95¥% confidence interval?

A: Given that sample size n = 670 And sample proportion = 0.85 The critical value of Z at 95%…

Q: Wisconsin Public Radio wants to duplicate a survey conducted in 2011 that found that 68% of adults…

A: From the provided information, Sample proportion (p̂) = 0.68 The z critical value at 90% confidence…

Q: Identify the at-score for a 99% confidence interval if the sample size is 70.

A: givensample size(n)=70α=1-0.99=0.01

Q: Wildlife biologists inspect 200 deer taken by hunters and find 45 of them carrying Lyme disease…

A: Given; x=45n=200Then the sample proportion is given by;p^=45200=0.225The level of significance…

Q: In a recent poll, 410 people were asked if they liked dogs, and 44% said they did. Find the margin…

A: n = 410 p^=0.44 Confidence interval = 95%

Q: In a recent poll, 500 people were asked if they liked dogs, and 94% said they did. Find the margin…

A:

Q: In a recent poll, 500 people were asked if they liked dogs, and 72% said they did. Find the margin…

A:

Q: In a recent poll, 100 people were asked if they liked dogs, and 90% said they did. Find the margin…

A: Obtain the margin of error at the 95% confidence level. The margin of error is obtained below as…

Q: According to a poll taken in a certain​ country, when adults were asked whether they were​ thriving,…

A: Sample size (n) = 439 240 of them said that they were struggling that is x = 240. The sample…

Q: Aston’s Career Service wants to find out what proportion of Aston’s students work in a part-time…

A: From the given information, Population proportion = p = 60% = 0.60 Margin of error = E = 4% = 0.04…

Q: In a clinical trial among 4441 patients treated with a drug; 5% developed a nausea reaction.…

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.