In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95% confidence interval for the population proportion of people who snooze the alarm in the morning.

Q: If a retailer would like to estimate the proportion of their customers who bought an item after…

A: Given data,     P=58%=0.58     E=7%=0.07     z-value at 95% confidence is  zc =1.98     n=?

Q: Find the 95% confidence interval for the mean difference of the tests, and explain it.

A: Test - 1 (X) Test-2 (Y) (x-xbar) (x-xbar)^2 (y-ybar) (y-ybar)^2 1.2 1.4 -0.31111 0.09679 -0.24444…

Q: In a random sample of 145 UNO students, we find that 53% have attended a Maverick hockey game at…

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Q: In a sample of 100,40 said they preferred Pepsi to Coke. A 95% confidence interval for the…

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Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: In a recent poll, 340 people were asked if they liked dogs, and 31% said they did. Find the margin…

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Q: In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that…

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Q: In a recent Dew Research Poll, 500 U.S. adults were asked about their online versus in-store clothes…

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Q: In a recent poll, 260 people were asked if they liked dogs, and 13% said they did. Find the margin…

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Q: In a recent poll, 430 people were asked if they liked dogs, and 41% said they did. Find the margin…

A: It is given that the value of n is 430, p hat is 0.41 and the confidence level is 0.99.

Q: We would like to know: "What percentage of college students drink alcohol every day?" In a random…

A: Given that, N=500 X=75

Q: In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that…

A: Given that Sample size n= 500  Favorable cases x=160 Sample proportion p^=x/n

Q: In a sample of 100, 40 said they preferred Pepsi to coke. A 95% confidence interval for the…

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Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

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Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

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Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: In a recent poll, 500 people were asked if they liked dogs, and 54% said they did. Find the margin…

A: Here we need to find the Margin of error corresponding to 95% confidence level.

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Solution:There is no estimates available, hence the sample proportion is assumed to be 0.50.The…

Q: In a recent poll, 150 people were asked if they liked dogs, and 55% said they did. Find the margin…

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Q: In a recent poll, 600 people were asked if they liked dogs, and 58% said they did. Find the margin…

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Q: in a survey of 2230 adults, 57% thinks that land travel through a tourist bus is much more reliable…

A: Given,sample size(n)=2230sample proportion(p^)=0.57α=1-0.95=0.05α2=0.025Z0.025=1.96       (from…

Q: In a survey of 7100 t.v views, 40% said they watch network news programs. Find the margin of error…

A: Solution: From the given information, p-hat=0.40 and n=7100. The confidence level is 0.95.

Q: Seventy-three percent of a sample of 1000 students drive a used car as opposed to a new car or no…

A: Given: Proportion  = 73 % Confidence level  = 80 %

Q: Of 91 adults selected randomly from one town, 60 have health insurance. Find a 90% confidence…

A: From the provided information, Sample size (n) = 91 Out of which 60 have health insurance. Sample…

Q: In a recent poll, 300 people were asked if they liked dogs, and 73% said they did. Find the margin…

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Q: In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education. Find…

A: Ans- Given the level of confidence interval   90 %                                        Then   α =…

Q: In a recent poll, 260 people were asked if they liked dogs, and 67% said they did. Find the margin…

A: Given: p = 67%=0.67 n= 260 The value of z at a 90% confidence level is 1.645, which can be found by…

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: 9. A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

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Q: A research institute poll asked respondents if they felt vulnerable to identify a theft. In the poll…

A: Given,n=1000x=501p^=xnp^=5011000=0.5011-p^=1-0.501=0.499α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a sample of 600 Ottawa families, it is found that 360 rent their dwellings while 240 own their…

A: It is given that sample size (n) is 360 and x is 240.

Q: In a recent survey of 500 teenagers, 18.6% indicated that they had eaten junk food while watching TV…

A: Given Data: p^=0.186n=500

Q: Is 12 minutes the margin of error for this 95% confidence interval v [Select ]

A: The 95% confidence interval for the average arrival time before departure for all air travellers is…

Q: Find a 90% confidence interval for the true proportion of people that eat frog legs, if in a sample…

A: Given, n = 732 p = 0.65 1 - α = 0.90α = 0.1α2 = 0.05   To find, 90% confidence interval for the true…

Q: A survey​ asks, "If the husband in a family wants​ children, but the wife decides that she does not…

A: We have to create 99% confidence interval for the population proportion.

Q: A random sample of accountants were asked whether they double-check their calculations on a tax…

A: Here the sample proportion is given by, p^ Therefore α level confidence interval is given by, p^ -…

Q: In a recent poll, 110 people were asked if they liked dogs, and 40% said they did. Find the margin…

A: For 99% confidence intervalα=1-CI=1-0.99=0.01So, zα2=z0.012=z0.005=2.576

Q: Identify the t- scores for a 99% confidence interval if the sample size is 70?

A: We have to find critical value.

Q: Wildlife biologists inspect 200 deer taken by hunters and find 45 of them carrying Lyme disease…

A: Given; x=45n=200Then the sample proportion is given by;p^=45200=0.225The level of significance…

Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: In a certain state, a survey of 500 workers showed that 38% belonged to a union.  Find the 93%…

A: Computation of critical value: 1-α=0.93α=0.07α2=0.0351-α2=0.965 The critical value of z-distribution…

Q: In a recent poll, 500 people were asked if they liked dogs, and 72% said they did. Find the margin…

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Q: A recent survey of 1,000 people found that 90% of Americans support background checks for purchasing…

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Q: confidence interval for the true proportion

A: We have to find out the confidence interval for the true proportion.

Q: According to a poll taken in a certain​ country, when adults were asked whether they were​ thriving,…

A: Sample size (n) = 439 240 of them said that they were struggling that is x = 240. The sample…

Q: A survey found that out of 800 workers, 150 said they were interrupted by frank phone calls. Find…

A: Given,n=800x=150p^=xnp^=150800=0.18751-p^=1-0.1875=0.8125α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: A study of 150 randomly selected accidents that involved trips to the emergency room found that 36%…

A: Given 99% confidence level, significance level α=1-0.99=0.01

Q: 2. A survey found that out of 900 workers, 150 said that they were interrupted by frank phone calls.…

A: In question, We have given the number of favorable cases 150 and sample size 900 then we'll find 95%…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.