A volume of 5.0 L of polluted air at 18.0°C and 747 mmHg is passes through limewater [an aqueous suspension of Ca(OH)2], so all the carbon dioxide is precipitated as CaCO3. If the mass of the CaCO3 precipitated is 0.023 g, calculate the percentage by volume CO, in the air sample.

A volume of 5.0 L of polluted air at 18.0°C and 747 mmHg is passes through limewater [an aqueous suspension of Ca(OH)2], so all the carbon dioxide is precipitated as CaCO3. If the mass of the CaCO3 precipitated is 0.023 g, calculate the percentage by volume CO, in the air sample.

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter6: The Gaseous State

Section: Chapter Questions

Problem 6.63QE

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

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A volume of 5.0 L of polluted air at 18.0°C and 747 mmHg is passes through limewater [an aqueous
suspension of Ca(OH)2], so all the carbon dioxide is precipitated as CaCO3. If the mass of the CaCO3
precipitated is 0.023 g, calculate the percentage by volume CO, in the air sample.

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