A W14x90 is used as a simply supported, uniformly loaded beam with a span length of 40 feet and continuous lateral support. The yield stress, Fy, is 50 ksi. If the ratio of live load to dead load is 2.5, compute the available strength and determine the maximum total service load, in kips/ft, that can be supported. (Hint: This is not a compact shape!)
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- 1. A W21 × 48 is used as a simply supported, uniformly loaded beam with a span length of 50 feet and continuous lateral support. The yield stress, Fy, is 60 ksi. If the ratio of live load to dead load is 3, compute the available strength and determine the maximum total service load (D+L), in kips/ft, that can be supported considering the flexure and shear strength of the beam. a. Use LRFD. b. Use ASD.A simply supported beam subjected to a uniform service Dead load of 20kn/m (including the weight of the beam), a uniform service live load of 35kn/m. The beam is 12m long and is laterally supported at midspan, and A572 Gr. 50 steel is used. Assuming cb =1. Verify if w30x108 is adequate? Use fy=344 mpaThe compression member shown is made of HE300B section. If Fy is equal to 320 MPa:a) Check the section for local buckling. b) Determine the maximum compressive service load that can be supported if the live load is twice as large as the dead load.
- A 12 ft long W12 × 96 (50 ksi steel) is used as a beam-column in a braced frame. It is bent in single curvature with equal and opposite end moments and is not subjected to intermediate transverse loads. Is the section satisfactory if ?? = 175 kips, ?? = 300 kips, and first-order ??? = 60 ft-kips and ??? = 60 ft-kips?A simply supported beam with a span of 9.5 m has a uniformly distributed dead load (including the beam weight) of 35 kN/m and live load of 30 kN/m. Use fc’ = 31 MPa, fy = 420 MPa, n = 6.8, and bar diameter of 32 mm. Determine the moment capacity (kN m) of the section under WSD conditions SHOW COMPLETE SOLUTION. NEED ASAP. THANK YOU.A W18x55 made by A992 steel is used on a simply supported beam. The beam span is 15ft and has lateral support of compression flange at its ends only. If the only dead load present is the beam self-weight, what is the largest service concentration live loads that can be placed at the 1/3 points of the beam? Assume the two concentrated loads are equal to each other. (Note: please determine the correctly).
- The loads for a 40’ simply-supported beam are as follows: • Dead Load, D = 600 plf • Live Load, L = 1000 plf Two load combinations need to be considered: a. 1.4D b. 1.2D + 1.6L Given these two load combinations, what is the maximum reaction to be used for the design of the member for strength, assuming the beam is simply-supported? What load (i.e., load combination) should be used to check the maximum service deflection?A reinforced concrete T- beam, section in Figure 2 (a), is subjected to an ultimate uniformload and concentrated loads as shown in the Figure 2(b). The beam is reinforced with 6-28 mm diameter tension bars at the point of maximum positive moment (at midspan -bars at the bottom), and 3-28 mm diameter tension bars at the point of maximum negativemoment (at the supports - bars at the top) .. The design properties used are: f ‘c = 21MPa and fy = 414 MPa, ; flange width = 650 mm, flange thickness is = 90 mm; webthickness = 250 mm; effective depth = 410 mm. Need to answer Q. Determine the safe value of Pu as required by flexure at the point of maximumpositive momentA W530 × 72 is used as a simply supported, uniformly loaded beam with a span length of 15 meters and continuous lateral support. The yield stress, ??, is 414 MPa. If the ratio of live load to dead load is 3, compute the available strength and determine the maximum total service load, in kN/m, that can be supported.
- From load analysis, the following are the factored design forces result: Mu = 440 KN-m, Vu = 280 KN. The beam has a width of 400 mm and a total depth of 500 mm. Use f’c = 20.7 MPa, fy for main bars is 415 MPa, concrete cover to the centroid of the bars both in tension and compression is 65 mm, steel ratio at balanced condition is 0.02, lateral ties are 12 mm diameter. Normal weight concrete. Calculate the required area of compression reinforcement in mm2 due to the factored moment, Mu. Express your answer in two decimal places.For a 250 mm x 450 mm powerful length singly strengthened beam, locate moment of resistance. Use concrete grade M 20 and metallic grade Fe 415.A rectangular beam has a clear span of 8.0m and carries a service live load of 100KN/m and a dead load of 75KN/m including its own weight. The beam has a width of 300mm and an effective depth of 500mm. It is reinforced with 4- 32mm rebar in two rows. Total depth of the beam is 600mm with F'c = 32MPa, Fy = 415MPa, Fyt = 276MPa. Use normal weight concrete. a. Using simplified calculation method for shear strength for concrete, determine the shear strength of concrete. b. Using Detailed calculation method for shear strength for concrete, determine the shear strength of concrete.