Hybrid vehicle. FIGURE P1 shows the block diagram of a possible cascade control scheme for anHEV driven by a dc motor (Preitl, 2007).The block diagram of the speed control of an HEV taken from FIGURE P1, and rearranged as aunity feedback system is shown in FIGURE P2. Here the system output is C(s) = Kss V(s), the outputvoltage of the speed sensor/transducer.pC, Av,-Speed K, Gre(s)controller commandTorque Amplifiercontroller output& power voltageamplifierAcro-Motive dynamieArmatureSpeed|drag torqueAngularspeed,Ref.circuit ArmaturetorqueVehiclesignalR,(s).errorU(s)T(s)T,(s)currentE,(s)speed, V(s)Gse(s)K, Grc(s)R.totFrictionFeedbackspeed signalKss2(s)Feedbacktorquecurrent signalKes I(S)T,(s)E,(s)Back emfD=kksCurrent sensorsensitivityKcsSpeed sensorsensitivityKssFIGURE P1 Hybrid VehicleR (s),E (s)Uc(s)|C(s)+Gsc(s)0.11 (s + 0.6)SCs (s + 0.5173) + 5 (s + 0.6) (s + 0.01908)URE P2 Block diagram of the speed control of an HEVa. Assume the speed controller is given as Gsc(s) = Kpsc . Find the gain, Kpsc , that yields asteady-state error, estep(∞) = 1%. Show your calculations, Simulink work and the results.b. Now assume that in order to reduce the steady-state error for step inputs, integration is addedto the controller yielding Gsc(s) = Kpsc +(K1sc/s)=100+(K1sc/s) Find the value of the integralgain, Kısc , that results in asteady-state error, eramp( 0)=2.5%. Show your calculations,%3DSimulink work and the results.c. Design an active controller [new Gsc(s)] such that the system can operate with a settling timeof 4 seconds and less than 5% overshoot and with zero steady-state error for a step input.Show your calculations, Simulink work and the results (draw the root locus of compensatedand uncompensated system).

Matlab code (with comments to explain): s-tf('s); % Defint transfer function variable 's' % Given…

a. Assume the speed controller is given as Gsc(s) = Kpsc . Find the gain, Kpsc, that yields a steady-state error, estep() = 1%. Show your calculations, Simulink work and the results. b. Now assume that in order to reduce the steady-state error for step inputs, integration is added to the controller yielding Gsc(s) = KpSc +(K1sc/s)=100+(K1sc/s) Find the value of the integral gain, KIsc , that results in asteady-state error, eramp(0)=2.5%. Show your calculations, Simulink work and the results. c. Design an active controller [new Gsc(s)] such that the system can operate with a settling time of 4 seconds and less than 5% overshoot and with zero steady-state error for a step input. Show your calculations, Simulink work and the results (draw the root locus of compensated and uncompensated system).

a. Assume the speed controller is given as Gsc(s) = Kpsc . Find the gain, Kpsc, that yields a steady-state error, estep() = 1%. Show your calculations, Simulink work and the results. b. Now assume that in order to reduce the steady-state error for step inputs, integration is added to the controller yielding Gsc(s) = KpSc +(K1sc/s)=100+(K1sc/s) Find the value of the integral gain, KIsc , that results in asteady-state error, eramp(0)=2.5%. Show your calculations, Simulink work and the results. c. Design an active controller [new Gsc(s)] such that the system can operate with a settling time of 4 seconds and less than 5% overshoot and with zero steady-state error for a step input. Show your calculations, Simulink work and the results (draw the root locus of compensated and uncompensated system).

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter12: Power System Controls

Section: Chapter Questions

Problem 12.2P

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