a. Calculate ΔH°f for methane (you will need to dust off Hess’s Law for this one, and recall that the heat of formation, ΔH°f , is the amount of energy required to form 1 mol of a substance from the elements under standard conditions- start by writing a balanced equation for this process.). b. From appropriate entropy data, calculate ΔS°f for methane. c. Use the above information to calculate ΔG°f for methane. d. Compare your results from part C with the reported ΔG°f for methane
a. Calculate ΔH°f for methane (you will need to dust off Hess’s Law for this one, and recall that the heat of formation, ΔH°f , is the amount of energy required to form 1 mol of a substance from the elements under standard conditions- start by writing a balanced equation for this process.). b. From appropriate entropy data, calculate ΔS°f for methane. c. Use the above information to calculate ΔG°f for methane. d. Compare your results from part C with the reported ΔG°f for methane
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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a. Calculate ΔH°f for methane (you will need to dust off Hess’s Law for this one, and recall that the heat of formation, ΔH°f , is the amount of energy required to form 1 mol of a substance from the elements under standard conditions- start by writing a balanced equation for this process.).
b. From appropriate entropy data, calculate ΔS°f for methane.
c. Use the above information to calculate ΔG°f for methane.
d. Compare your results from part C with the reported ΔG°f for methane
Transcribed Image Text:Selected thermodynamic data at 298 K.
Substance
AH°t (kJ/mol)
AG°f (kJ/mol)
S° J/mol-K)
PC13(g)
-319.6
-272.4
217
Oz(g)
205.0
POC1:(g)
-542.2
-502.5
325
C(graphite)
5.69
H2(g)
130.58
CH4(g)
?
-50.8
186.3
Transcribed Image Text:ΔΗ(Κ)
CO2(8) + 2H2(8) →> CH2O(g) + H2O(g)
CO2(8) → C(graphite) + O2(g)
CH2O(g) + 2H2(3) → CH«(8) + H2O(g)
2H2(g) + O2(8) → 2 H2O(g)
35.5
393
-201
-484
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