A1 A2 A3 A4 B1 13 3 B2 4 11 B3 7 3 10 4 B4 8 Use values from the contingency table to calculate the following: // Gebruik waardes uit die gebeurlikheidstabel om die volgende te bereken: Σ (x,, - i) = ?
Q: 1. The number of heart patients diagnosed in each of seven leading cities in the Philippines in 1992…
A: Pie chart is the type of graph that used to represent one variable with different levels. It also…
Q: University Dean wishes to estimate the average number of hours that freshmen study each week. The…
A: Solution
Q: Starship Media Entertainment's budget director, Ms. Janice Hammington, wanted to compare the daily…
A:
Q: 21. Television Watching The average number of hours of television watched per week by women over age…
A: Given that Sample sizes n1=40 , n2=40 Sample means X̄1=48.2 , X̄2=44.3 ?1…
Q: Problem: In a nationwide survey, 1,500 adults were asked about attitudes toward "alternative…
A: Given that Sample size n =1500 Favorable cases x =660 Sample proportion p^=x/n =660/1500 =0.44
Q: If x-y? (5), then p(0.554 < x < 15.09) (using x? table) 0.980 0.950 0.05
A: We have given that, X ~ χ2(5) Then, We will find fine probability P(0.554 <X<15.09) = ?
Q: A climatologist has been collecting sulfur dioxide readings from a sample of monitoring sites…
A:
Q: Question 13 The claim is a mean is 212 and you want to prove it is more. Test the hypothesis within…
A: According to the given information in this question Given Test statistic = 0.26 Decision = 1.8
Q: Consider the data with analysis shown in the following computer output: Level N Mean StDev A…
A: For the given data Find The pooled standard deviation is = ?degrees of freedom = ?
Q: In 2010, 91% of households had at least one cell phone. A random sample of 300 households in each of…
A:
Q: drink filling machine, when in perfect adjustment, fills the bottles with 16 ounces of soft drink. A…
A: Given that ; u = 16 Sample mean = 15.28 S = 0.24 n = 25 By using 0ne sample mean test we solve…
Q: 3. A survey of households connected to North Park Secondary Night School found that 96% had Netflix…
A: Disclaimer : Since you have asked multiple question, we will solve the first question for you. If…
Q: Suppose that the number of Facebook friends users have is normally distributed with a mean of 146…
A: Mean(µ) = 146Standard deviations (σ) = 44 X ~ N (µ, σ )= N (146, 44) n = 47 Mean= µx̅ = µ = 146 σx̅…
Q: Example 24. The following table represents the marks obtained by a batch of 12 students in certain…
A:
Q: plot back-to-back with the previous stemplot. For #5, make your boxplots side-by- side. PART II:…
A: Hi! Thank you for the question, As per the honour code, we are allowed to answer three sub-parts at…
Q: II. Explain which of the following constitute a population and which constitute a sample. Number of…
A: Q
Q: A financial officer for a company wants to estimate the percent of accounts receivable that are more…
A: It is given that Sample size n = 500 Number of accounts that are more than 30 days overdue, X = 300…
Q: If a randomly selected person from the survey drives a what is the probability that he is a 'male"?
A: Solution
Q: x-2 If x-N(2, 4), then ..... ..... G ,2 (1) Option 2 Option 3 N(0,1) Option 1
A: Given that, x~N(2, 4) And We have to find the distribution of x-2/2~... ... ...
Q: According to a Harvard Health Publishing article, the normal body temperature may be lower than…
A:
Q: A population of a certain LGBT+ community is consists of 6 measurements 2,3,6,9,11 and 5 1.) What…
A:
Q: Briefly explain what is meant by the term “descriptive statistics”.
A: We have to describe descriptive statistics here
Q: Studies suggest that women who smoke during pregnancy affect the birth weights of their newborn…
A: Disclaimer : “Since you have posted a question with multiple sub-parts, we will solve first three…
Q: The following contingency table records some information about a sample of visitors to Old Fort…
A: Given that ; Chi square = 17.0 A (3 × 5 ) Contigency table is given. By using chi square concept we…
Q: The length of time that it takes to be served in a supermarket is an example of: a)…
A:
Q: Create a histogram for the following data: the number of books bought by 50 part-time college…
A: class will be calculated by (upper limit-lower limit)/2 on the basis of class interval the histogram…
Q: automobile club comes to the aid of stranded motorists who are members. Over the long run, about 10%…
A: Given that; Sample size (n) = 230 Proportion = 10 % By using one sample proportion test we solve…
Q: 4) and 28% are enrolled in a foreign language course. Of those enrolled in a psychology course, 32%…
A: We have given that P( psychology) = 17% = 0.17 P( foreign language) = 28% = 0.28 P( foreign…
Q: An experiment has been conducted for four treatments with eight blocks. Complete the following…
A: Given: Four treatments with eight blocks.
Q: eck for difference in variances? To determine whether the z-table or the t-table should be used. To…
A: Given that ; I solved this question by using the assumptions of difference in means.
Q: accept a flyer as they pass by follows a Poisson distribution with the rate of u = 4 people per…
A: Since you have posted a question with multiple sub-parts, as per our guidelines, we have provided…
Q: Suppose that in a random sample of 600 employed Americans, there are 55 individuals who say that…
A:
Q: Explain why the critical value of t, one-tailed, alpha = .05 is the same as the critical value of t,…
A:
Q: For each of the scatter plots below, determine whether there is a perfect positive linear…
A:
Q: determine who drives either an electric vehicle or a combustion vehicle Electric 43 37 Combustion 42…
A: Given Information: Total no. of participants=177 Total no. of males =85 No. of males driving…
Q: live from the school. The results are shown in the h Distance from School 10 8 7 6 5 3 2 1 0-1.9…
A: Given Information: S.No. Distance from school No. of students cumulative frequency 1. 0-1.9 5 5…
Q: Let (x1, x2, ..., ¤n) be a random sample from a Poisson distribution with parameter 0 > 0. Show that…
A:
Q: Heights for group of people normally distributed with mean = 65 inches and standard deviation = 2.5…
A:
Q: Let f(y, A) be the density function of a continuous random variable, Y, where A is the parameter of…
A: (a) Parametric Family of densities: Due to the presence of one or more shape parameters, the density…
Q: %3D %3D %3D Compute for the corresponding z-score, given that x = 93.35, µ = 84, and o = 11.
A: Given information X = 93.35 mu = 84 Std = 11 Z score = (x - mu)/std
Q: Match the terms below to their best definitions. The value occurring most often in a group of cases.…
A: Mode is the value occuring most often in a group of cases. Scatter plot is the best way to…
Q: elsewnere a) What is the marginal distribution of Z2. b) Find P(Z, s4)
A:
Q: If B = .75, power = %3D
A: From the provided information, The value of beta (β) = 0.75
Q: .2.7 Data that is generated at source for the first time is referred to as: a) Discrete data b)…
A: Primary data: The data obtained from original experiments or surveys, i.e, the data collected by…
Q: (a) show that Z = – In Y; has exponential distribution with parameter 1. (b) Hence or otherwise,…
A:
Q: How many cases are there in this data set 864 216 432 1 forest
A: We have given that the resulting spatial pattern could be tested to see whether the pattern is…
Q: Mario made a claim that 95% of college male students in their school join triathlon. His friend,…
A: Given that Sample size n =90 Favorable cases x=75 Sample proportion p^=x/n
Q: Theorem;- Sample mean is unboise estimate of POpulation mean in poission distribution CS Scanned…
A: In question, We'll prove that sample mean is unbiased estimator of population mean for Poisson…
Q: uppe ropc
A: dist <- tibble(p_grid = seq(from = 0, to = 1, length.out = 20))%>% mutate(prior = case…
Q: p= 0.04 probability that a random respondent will express support for LOLF. During a poll exactly…
A:
Step by step
Solved in 2 steps with 2 images
- The Stanford University Heart Transplant Study was conducted to determine whether an experimental heart transplant program increased lifespan. Each patient entering the program was designated an official heart transplant candidate, meaning that he was gravely ill and would most likely benefit from a new heart. Patients in the treatment group got a transplant and those in the control group did not. Of the 34 patients in the control group, 4 were alive at the end of the study. Of the 69 patients in the treatment group, 24 were alive. The contingency table below summarizes these results.Any athlete who fails the Enormous State University's women's soccer fitness test is automatically dropped from the team. Last year, Mona Header failed the test, but claimed that this was due to the early hour. (The fitness test is traditionally given at 5 AM on a Sunday morning.) In fact, a study by the ESU Physical Education Department suggested that 48% of athletes fit enough to play on the team would fail the soccer test, although no unfit athlete could possibly pass the test. It also estimated that 42% of the athletes who take the test are fit enough to play soccer. Assuming these estimates are correct, what is the probability that Mona was justifiably dropped? (Round your answer to four decimal places.)Globally, 35% of all ridged brittleshell tortoises have spots on their shells. A herpetologist in Citition collects a sample of 38 ridged brittlesell tortoises and finds that 16 of them have spots on their shells. The herpetologist would like to test the claim that the proportion of ridged brittleshell tortoises in Cititon with spots on their shells is greater than 35%. The herpetologist ends up rejecting the null hypothesis. If the actual proportion of ridged brittleshell tortoises in Cititon with spots on their shells is 41%, then what type of error, if any, has occurred? In the problem above, what is the test statistic?
- Kentville, a community of 10,000 people, resides next to a krypton mine, and there is a concern that the emission from the krypton smelter have resulted in adverse effects. Specifically, Kryptonosis seems to have killed 12 of Kentville’s inhabitants last year. A neighboring community, Lanesburg, has 25,000 inhabitants and is far enough from the smelter to not be affected by the emission. In Lanesburg, only three people last year died of Kryptonosis. Given that the number of deaths in Kentville and their causes last year were: Heart attack=7 Accidents=4 Kryptonosis=12 Other=6 What is the risk of dying of Kryptonosis in Kentville relative to non-contaminated locality?What is the risk of dying of Kryptonosis in Kentville relative to deaths due to other causes? How many times the chance of dying of Kryptonosis compared to dying of accidents ? How many times the chance of dying of Kryptonosis compared to Other causes?Suppose that a healthy person has 10% chance of getting sick that would require $40,000 of medical expenses. Suppose that unhealthy person has a 60% chance of getting sick that would require $100,000 in medical expenses. A) What would be an actuarially fair premium for a healthy person? B) What would be an actuarially fair premium for unhealthy person? C) If everyone has to buy health insurance and 20% of the population are unhealthy and 80% of the population are health, what would be an actuarially fair premium for any person?The quality department at an electronics company has noted that, historically, 91% of the units of a specific product pass a test operation, 6% fail the test but are able to be repaired, and 3% fail the test and need to be scrapped. Due to recent process improvements, the quality department would like to test if the rates have changed. A recent sample of 500 parts revealed that 473 parts passed the test, 20 parts failed the test but were repairable, and 7 parts failed the test and were scrapped. (You may find it useful to reference the appropriate table: chi-square table or table)a. Choose the appropriate alternative hypothesis for the test.
- According to the Pew Research Center, the proportion of the American population who use only a cellular telephone (no landline) is 0.37. Jason conducts a survey of thirty 20- to 24-year-olds who live on their own and finds that 16 do not have a landline to their home. Does this provide sufficient evidence to conclude that the proportion of 20- to 24-year-olds who live on their own and don’t have a landline is greater than 0.37? Use an a=0.10 level of significance. NoteAn insurance company offers four different deductible levels—none, low, medium, and high—for its homeowner’s policyholders and three different levels—low, medium, and high—for its automobile policyholders. The accompanying table gives proportions for the various categories of policyholders who have both types of insurance. For example, theproportion of individuals with both low homeowner’s deductible and low auto deductible is .06 (6% of all such individuals).Suppose an individual having both types of policies is randomly selected.a. What is the probability that the individual has a medium auto deductible and a high homeowner’s deductible?b. What is the probability that the individual has a low auto deductible? A low homeowner’s deductible?c. What is the probability that the individual is in the same category for both auto and homeowner’s deductibles?d. Based on your answer in part (c), what is the probability that the two categories are different?e. What is the probability that the…IN excel if possibleGreat Grasslands Grains, Inc. (GGG) manufactures and sells a wide variety of breakfast cereals. GGG’sproduct development lab recently created a new cereal that consists of rice flakes and banana-flavoredmarshmallows. The company’s marketing research department has tested the new cereal extensivelyand has found that consumers are enthusiastic about the cereal when 16-ounce boxes contain at least1.6 ounces and no more than 2.4 ounces of the banana-flavored marshmallows.As GGG prepares to begin producing and selling 16-ounce boxes of the new cereal, which it has namedGo Bananas management is concerned about the amount of banana-flavored marshmallows. It wants tobe careful not to include less than 1.6 ounces or more than 2.4 ounces of banana-flavoredmarshmallows in each 16-ounce box of Go Bananas. Tina Finkel, VP of Production for GGG, hassuggested that the company measure the weight of banana-flavored marshmallows in a random sampleof 25 boxes of Go Bananas on a weekly…
- A quality engineer samples 100 steel rods made on mill A and 150 rods made on mill B. Of the rods from mill A, 88 meet specifications, and of the rods from mill B, 135 meet specifications. a) Estimate the proportion of rods from mill A that meet specifications, and find the uncertainty in the estimate. b) Estimate the proportion of rods from mill B that meet specifications, and find the uncertainty in the estimate. c) Estimate the difference between the proportions, and find the uncertainty in the estimate.An organization published an article stating that in any one-year period, approximately 8.2 percent of adults in a country suffer from depression or a depressive illness. Suppose that in a survey of 100 people in a certain town, six of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult population in the country. p' = Calculate ?x. Find the p-value.A certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time. A recent sample of 1,000 adults showed 410 indicating that their financial security was more than fair. Suppose that just a year before, a sample of 1,200 adults showed 420 indicating that their financial security was more than fair. (a) State the hypotheses that can be used to test for a significant difference between the population proportions for the two years. (Let p1 = population proportion most recently saying financial security more than fair and p2 = population proportion from the year before saying financial security more than fair. Enter != for ≠ as needed.) H0: p1−p2=0 Ha: p1−p2!=0 (b) Conduct the hypothesis test and compute the p-value. At a 0.05 level of significance, what is your conclusion? Find the value of the test statistic. (Use p1 − p2. Round your answer to two decimal places.) Find the p-value.…
