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According to an officer in the Health Care Financing Administration, the average annual expenditure on toiletries is RM110 per person in Malaysia. The data of 30 randomly selected persons are as follows and the standard deviation of the sample is 19.2152. 125 110 110 90 90 85 125 110 85 120 130 125 130 90 130 80 120 90 110 90 90 85 100 130 80 90 100 125 150 100 i. Find the sample mean of the data. Is there enough evidence to support the officer's claim at 0.02 level of significance? iii. What is the decision at a 0.2% significance level? ii.

According to an officer in the Health Care Financing Administration, the average annual expenditure on toiletries is RM110 per person in Malaysia. The data of 30 randomly selected persons are as follows and the standard deviation of the sample is 19.2152. 125 110 110 90 90 85 125 110 85 120 130 125 130 90 130 80 120 90 110 90 90 85 100 130 80 90 100 125 150 100 i. Find the sample mean of the data. Is there enough evidence to support the officer's claim at 0.02 level of significance? iii. What is the decision at a 0.2% significance level? ii.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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According to an officer in the Health Care Financing Administration, the average annual expenditure on toiletries is RM110 per person in Malaysia. The data of 30 randomly selected persons are as follows and the standard deviation of the sample is 19.2152. 125 110 110 90 90 85 125 110 85 120 130 125 130 90 130 80 120 90 110 90 90 85 100 130 80 90 100 125 150 100 i. Find the sample mean of the data. Is there enough evidence to support the officer's claim at 0.02 level of significance? iii. What is the decision at a 0.2% significance level? ii.
Transcribed Image Text:According to an officer in the Health Care Financing Administration, the average annual expenditure on toiletries is RM110 per person in Malaysia. The data of 30 randomly selected persons are as follows and the standard deviation of the sample is 19.2152. 125 110 110 90 90 85 125 110 85 120 130 125 130 90 130 80 120 90 110 90 90 85 100 130 80 90 100 125 150 100 i. Find the sample mean of the data. Is there enough evidence to support the officer's claim at 0.02 level of significance? iii. What is the decision at a 0.2% significance level? ii.
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