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According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select four peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places: your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the four M&M's are yellow: Compute the probability that two or three of the four M&M's are yellow: Compute the probability that at most two of the four M&M's are yellow:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select four peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places: your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the four M&M's are yellow: Compute the probability that two or three of the four M&M's are yellow: Compute the probability that at most two of the four M&M's are yellow:

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select four peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places: your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the four M&M's are yellow: Compute the probability that two or three of the four M&M's are yellow: Compute the probability that at most two of the four M&M's are yellow: Compute the probability that at least two of the four M&M's are yellow: If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be yellow? M&M's With what standard deviation? M&M's
Transcribed Image Text:According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select four peanut M&M's from an extra-large bag of the candies. (Round all probabilities below to four decimal places: your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the four M&M's are yellow: Compute the probability that two or three of the four M&M's are yellow: Compute the probability that at most two of the four M&M's are yellow: Compute the probability that at least two of the four M&M's are yellow: If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be yellow? M&M's With what standard deviation? M&M's
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