According to Table 7-1, the equilibrium percentage of the first molecule in its keto form is lower than that of the second molecule. Explain why. TABLE 7-1 Relative Percentages of Keto and Enol Forms Tautomerization Reaction Percent Keto Form Percent Enol Form 99.99994% 0.00006% 99.986% 0.014% 99.9999995% 0.0000005% H. 99.9999988% 0.0000012% H H. 99.99996% 0.00004%
According to Table 7-1, the equilibrium percentage of the first molecule in its keto form is lower than that of the second molecule. Explain why. TABLE 7-1 Relative Percentages of Keto and Enol Forms Tautomerization Reaction Percent Keto Form Percent Enol Form 99.99994% 0.00006% 99.986% 0.014% 99.9999995% 0.0000005% H. 99.9999988% 0.0000012% H H. 99.99996% 0.00004%
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter13: Substitution
Section: Chapter Questions
Problem 8CTQ
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Transcribed Image Text:According to Table 7-1, the equilibrium percentage of the first molecule in its keto form is
lower than that of the second molecule. Explain why.
Transcribed Image Text:TABLE 7-1 Relative Percentages of Keto and Enol Forms
Tautomerization Reaction
Percent Keto Form
Percent Enol Form
99.99994%
0.00006%
99.986%
0.014%
99.9999995%
0.0000005%
H.
99.9999988%
0.0000012%
H
H.
99.99996%
0.00004%
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