According to the diagram in the figure, indicate the true option. A) A is the fundamental electronic state; B the first excited electronic state and C the second. B) F and G are anti-Stokes transitions. C) D and E represent Rayleigh scatterings, since both excitations lead to the same energy state. D) Transition F is of the simple Stokes type; the G, of the double Stokes type. Energia DE F G B A
Electronic Transitions and Spectroscopy
The term “electronic” connotes electron, and the term “transition” implies transformation. In a molecule, the electrons move from a lower to a higher energy state due to excitation. The two energy states, the ground state and the excited state are the lowest and the highest energy states, respectively. An energy change is observed with this transition, which depicts the various data related to the molecule.
Photoelectron Spectroscopy
Photoelectron spectroscopy (PES) is a part of experimental chemistry. It is a technique used in laboratories that involves projecting intense beams of radiation on a sample element. In response, the element ejects electrons for which the relative energies are measured.
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