Acetylene burns in air according to the following equation: ΔΗ. AH СН (g) + O23) — 2 СО,(g) На0(g) =-1255.8 kJ rxn Given AH of CO2(g) =-393.5 kJ/mol and AH of H20(g)-241.8 kJ/mol, find AH of C2H2(g). f kJ/mol

Physical Chemistry
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Chapter2: The First Law Of Thermodynamics
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Problem 2.93E: Find the enthalpies of the combustion reactions for methane through n-octane. Plot them versus the...
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Acetylene burns in air according to the following equation:
ΔΗ.
AH
СН (g) +
O23) — 2 СО,(g)
На0(g)
=-1255.8 kJ
rxn
Given AH
of CO2(g) =-393.5 kJ/mol and AH of H20(g)-241.8 kJ/mol, find AH of C2H2(g).
f
kJ/mol
Transcribed Image Text:Acetylene burns in air according to the following equation: ΔΗ. AH СН (g) + O23) — 2 СО,(g) На0(g) =-1255.8 kJ rxn Given AH of CO2(g) =-393.5 kJ/mol and AH of H20(g)-241.8 kJ/mol, find AH of C2H2(g). f kJ/mol
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