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As a measure of productivity, a cell phone company records the number of customers each of its retail employees activates weekly. An activation is defined as either a new customer signing a cell phone contract or an existing customer renewing a contract. The accompanying table shows the number of weekly activations for eight randomly selected employees along with their job-satisfaction levels rated on a scale of 1-10 (10 = Most satisfied). Complete parts a through d. E Click the icon to view the table showing activations and satisfaction. The coefficient of determination is 0.674. (Type an integer or decimal rounded to three decimal places as needed.) b. Using a = 0.05, test the significance of the population coefficient of determination. The hypotheses for this test are Ho: p? = 0 and H,: p? > 0. The test statistic is 12.38 (Type an integer or decimal rounded to two decimal places as needed.) The p-value is 0.013 (Type an integer or decimal rounded to three decimal places as needed.) Therefore, at the 0.05 level of significance, reject the null hypothesis. There is sufficient evidence to conclude that the coefficient of determination is greater than zero. c. Construct a 95% confidence interval for the average number of activations made by an employee with a job-satisfaction score of 8.2. The confidence interval is ( ) (Type integers or decimals rounded to one decimal place as needed.)

As a measure of productivity, a cell phone company records the number of customers each of its retail employees activates weekly. An activation is defined as either a new customer signing a cell phone contract or an existing customer renewing a contract. The accompanying table shows the number of weekly activations for eight randomly selected employees along with their job-satisfaction levels rated on a scale of 1-10 (10 = Most satisfied). Complete parts a through d. E Click the icon to view the table showing activations and satisfaction. The coefficient of determination is 0.674. (Type an integer or decimal rounded to three decimal places as needed.) b. Using a = 0.05, test the significance of the population coefficient of determination. The hypotheses for this test are Ho: p? = 0 and H,: p? > 0. The test statistic is 12.38 (Type an integer or decimal rounded to two decimal places as needed.) The p-value is 0.013 (Type an integer or decimal rounded to three decimal places as needed.) Therefore, at the 0.05 level of significance, reject the null hypothesis. There is sufficient evidence to conclude that the coefficient of determination is greater than zero. c. Construct a 95% confidence interval for the average number of activations made by an employee with a job-satisfaction score of 8.2. The confidence interval is ( ) (Type integers or decimals rounded to one decimal place as needed.)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 36E
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ers each of its retail employees activates we of activations and satisfactic Activations Satisfaction O 37 8.0 22 7.9 37 8.5 37 9.0 18 6.1 27 7.0 32 8.2 28 77 Print Done ade by an employee with a job-satisfaction score of Doorson
Transcribed Image Text:ers each of its retail employees activates we of activations and satisfactic Activations Satisfaction O 37 8.0 22 7.9 37 8.5 37 9.0 18 6.1 27 7.0 32 8.2 28 77 Print Done ade by an employee with a job-satisfaction score of Doorson
As a measure of productivity, a cell phone company records the number of customers each of its retail employees activates weekly. An activation is defined as either a new customer signing a cell phone contract or an existing customer renewing a contract. The accompanying table shows the number of weekly activations for eight randomly selected employees along with their job-satisfaction levels rated on a scale of 1-10 (10 = Most satisfied). Complete parts a through d. E Click the icon to view the table showing activations and satisfaction. The coefficient of determination is 0.674 (Type an integer or decimal rounded to three decimal places as needed.) b. Using a = 0.05, test the significance of the population coefficient of determination. The hypotheses for this test are Ho: p² = 0 and H,: p? > 0. The test statistic is 12.38 (Type an integer or decimal rounded to two decimal places as needed.) The p-value is 0.013. (Type an integer or decimal rounded to three decimal places as needed.) Therefore, at the 0.05 level of significance, reject the null hypothesis. There is sufficient evidence to conclude that the coefficient of determination is greater than zero. c. Construct a 95% confidence interval for the average number of activations made by an employee with a job-satisfaction score of 8.2. The confidence interval is (). (Type integers or decimals rounded to one decimal place as needed.)
Transcribed Image Text:As a measure of productivity, a cell phone company records the number of customers each of its retail employees activates weekly. An activation is defined as either a new customer signing a cell phone contract or an existing customer renewing a contract. The accompanying table shows the number of weekly activations for eight randomly selected employees along with their job-satisfaction levels rated on a scale of 1-10 (10 = Most satisfied). Complete parts a through d. E Click the icon to view the table showing activations and satisfaction. The coefficient of determination is 0.674 (Type an integer or decimal rounded to three decimal places as needed.) b. Using a = 0.05, test the significance of the population coefficient of determination. The hypotheses for this test are Ho: p² = 0 and H,: p? > 0. The test statistic is 12.38 (Type an integer or decimal rounded to two decimal places as needed.) The p-value is 0.013. (Type an integer or decimal rounded to three decimal places as needed.) Therefore, at the 0.05 level of significance, reject the null hypothesis. There is sufficient evidence to conclude that the coefficient of determination is greater than zero. c. Construct a 95% confidence interval for the average number of activations made by an employee with a job-satisfaction score of 8.2. The confidence interval is (). (Type integers or decimals rounded to one decimal place as needed.)
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