Question
Asked Oct 22, 2019
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Expert Answer

Step 1

Given:

The differential equation is x2y" +xy'-y =2x2 +2
1
The two solutions are given as y = x andy2
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The differential equation is x2y" +xy'-y =2x2 +2 1 The two solutions are given as y = x andy2

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Step 2

Solution: 

2x22
1
1
The differential equation can be written as y"+-y'
For the differential equation y"+p(x)y'+q(x)y= g(x)
For ypxy'+q(x)y= 0, the solutions are y and y,
of parameters
The particy lar solution is ohted as
V1g (x)
particular
variation
the
solution
is
obtained
By
as
y28 (x
W(y1 y2)
W(Y2)
dx
help_outline

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2x22 1 1 The differential equation can be written as y"+-y' For the differential equation y"+p(x)y'+q(x)y= g(x) For ypxy'+q(x)y= 0, the solutions are y and y, of parameters The particy lar solution is ohted as V1g (x) particular variation the solution is obtained By as y28 (x W(y1 y2) W(Y2) dx

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Step 3

Calculatio...

Obtain the value of W (y, y) as follows
1
У.
W(y, y2)=
1
2
1 1
2
х
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Obtain the value of W (y, y) as follows 1 У. W(y, y2)= 1 2 1 1 2 х

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