AEth + OEb= O MCAT + [mOH|=0 (2.2)(2.05) (0+l96) + m(3385) m= 2.665 k

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter1: Physics And Measurement
Section: Chapter Questions
Problem 1.6OQ
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im tryin to calculate the final mass of ice starting at 2.2kg im not sure where this person got the m(3335) part from im hoping you can explain how this person got that

AE th+ OEb=0
MCAT + (mOH1-0
(2.2)(2.05) (0 196)
m= 2.665 kq
) + m(3385)
Transcribed Image Text:AE th+ OEb=0 MCAT + (mOH1-0 (2.2)(2.05) (0 196) m= 2.665 kq ) + m(3385)
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