Asked Sep 18, 2019

After staining an SDS-PAGE gel with Coomassie Blue G-250, the protein bands are visualized by de-staining the gel in a Coomassie Blue G-250 de-staining solution. This solution is made up of 10% acetic acid, 50% methanol, and 40% distilled water. How much of each of these components do you need to prepare 5 liters of Coomassie Blue G-250 de-staining solution?


Expert Answer

Step 1

Protein purification is the process in which a protein or a number of proteins are separated or isolated from other components of a cell or tissue. Isolation of protein is done by various processes like electrophoresis, chromatography, dialysis, and many more.

Step 2

The composition percentages of the components in the preparation of Coomassie Blue G-250 de-staining solution are as follows:

  • Acetic acid = 10%
  • Methanol = 50%
  • Distilled water = 40%...

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The amount of acetic acid is calculated below 10 Acetic acid100 - x 5 0.5liters The amount of Methanol is calculated below: 50 x 5 100 Methanol =2.5liters The amount of Distilled water is calculated below: 40 x 5 100 Distiled water =2liters


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