AH° for Ca(s) + 2 H,0(1) → Ca²*(aq)+2 OH-(aq) +H2(g). Known reactions: H*(aq) + OH- (aq) → H2O(!) AH° = – 55.9 kJ Ca(s) + 2H*(aq) → Ca²*(aq) + H2(g) AH° = – 543.0 kJ
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- Glycolysis is the process by which glucose is metabolized to lactic acid according to the equation C6H12O6(aq)2C3H6O3(aq) G=198 kJ at pH 7.0 and 25°C Glycolysis is the source of energy in human red blood cells. In these cells, the concentration of glucose is 5.0103 M, while that of lactic acid is 2.9103 M. Calculate AG for glycolysis in human blood cells under these conditions. Use the equation G=G+RT In Q, where Q is the concentration quotient, analogous to K.Give a clear handwritten answer??asapCr2O7 2- (aq) + 14H+ 6e- ---> Cr3+(aq) + 7H2O(l) Ered = 1.33V Cu2+(aq) + 2e- --> Cu(s) ?°red = 0.34V Determine the Ecell at 25°C, given: [Cr2O7(aq) 2- ] = 0.2500M ,[Cr(aq) 3+ ] = 0.2500M , pH =5 [Cu2+]=0.2500M
- Given that the Ksp for Ag2S is 6×10^-51, Kf=1.1×10^5 for AgCl2-, and Ka1 and Ka2 for H2S are 9.5×10^-8 and 1×10^-19, respectively, calculate the equilibrium constant for the following reaction .Consider the following data. For the acid: HA- Ka = 7.46⋅10−87.46⋅10-8 Calculate the Kb for A2-. Report your answer in scientific notation using 3 sig figs.How would the equilibrium be affected in regards to the value of Qc or Kc for each of the following conditions?: Fe3+ (aq) + SCN- (aq) ⇌ FeSCN2+ (aq) Adding KSCN (aq) Adding Fe(NO3) (aq) Adding NaF (s) Placing the solution into a hot water bath Placing the solution into an ice bath (To whom this may concern, Could you at least explain one as simply as possible so I'm able to understand the others enough to explain them myself? Thanks in anvance!)
- CH.8 #8 - Please fill in the blank, cirlce your answer for thumbs up!At constant pressure and 25 C, what is the Delta rH for the following reaction: 2C2H6 (g) + 7O2(g) --> 4CO2(g) + H2O(l) if the complete consumption of 12.5g of C2H6 liberates 752.3 kJ of heat energy?Choose from the options A-E and explain briefly by illustrations the chemistry behind each answer.
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