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We must first calculate the mass defect (Am) for 5oFe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of: Fe atom = mass of nucleus + 26 me 26 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 – 26 me) - [26(1.0078 – m) + 30(1.0087)]. Solve for Am. Am = X amu

We must first calculate the mass defect (Am) for 5oFe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of: Fe atom = mass of nucleus + 26 me 26 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 – 26 me) - [26(1.0078 – m) + 30(1.0087)]. Solve for Am. Am = X amu

Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Chapter10: Radioactivity And Nuclear Processes
Section: Chapter Questions
Problem 10.8E
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We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 56 Fe atom 26 = mass of nucleus + 26 me = mass of 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = X amu
Transcribed Image Text:We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 56 Fe atom 26 = mass of nucleus + 26 me = mass of 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = X amu
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