Air flows through a closed-circuit wind tunnel shown in Figure below at standard conditions through the test section [between sections (5) and (6)] with a velocity of x m/s. The flow is driven by a fan that essentially increases the static pressure by the amount p1 – p, that is needed to overcome the head losses experienced by the fluid as it flows around the circuit. Estimate the value of p - py and the horsepower supplied to the fluid by the fan. Vs = x m/s %3D (4) (5) (6) (7) Test section (3) Flow-straightening screens (8) Q (1). (9) V Automatic Hidden Arrow XA

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Air flows through a closed-circuit wind tunnel shown in Figure below at standard conditions through the
test section [between sections (5) and (6)] with a velocity of x m/s. The flow is driven by a fan that
essentially increases the static pressure by the amount p¡ – p, that is needed to overcome the head losses
experienced by the fluid as it flows around the circuit.
Estimate the value of p, – p, and the horsepower supplied to the fluid by the fan.
- P9
Vs = x m/s
(5)
(6)
(7)
Test section
Flow-straightening
(3)
screens
(8)
Q (1)
(9)
V Automatic
(2)
Hidden
Arrow
Pen
Fan
Transcribed Image Text:Review Questions Air flows through a closed-circuit wind tunnel shown in Figure below at standard conditions through the test section [between sections (5) and (6)] with a velocity of x m/s. The flow is driven by a fan that essentially increases the static pressure by the amount p¡ – p, that is needed to overcome the head losses experienced by the fluid as it flows around the circuit. Estimate the value of p, – p, and the horsepower supplied to the fluid by the fan. - P9 Vs = x m/s (5) (6) (7) Test section Flow-straightening (3) screens (8) Q (1) (9) V Automatic (2) Hidden Arrow Pen Fan
x = 64.06 m/s
Moreover, the area-velocity information at each location is as follows:
Location
Area (m?)
Velocity (m/s)
1
2
To be found
2
2.5
To be found
3
3.2
To be found
4
3.2
To be found
0.4
0.4
7
0.9
To be found
8
1.8
To be found
2.1
To be found
6.
Transcribed Image Text:x = 64.06 m/s Moreover, the area-velocity information at each location is as follows: Location Area (m?) Velocity (m/s) 1 2 To be found 2 2.5 To be found 3 3.2 To be found 4 3.2 To be found 0.4 0.4 7 0.9 To be found 8 1.8 To be found 2.1 To be found 6.
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