All bars in the truss have the same cross section and material. (1) The system must have a vertical displacement at point B of less than 0.065 in, and a maximum absolute value of the normal stress less than 24 ksi in all the bars. Based on these two constraints, find the allowable load P. (2) Assuming P = 8k, find the stress at point p in the coordinate system given. (1) P= |(2) σ= k ksi A = 0.24 in² E=30000 ksi V = 0.29 point p A B YP 6 ft C P 8 ft
All bars in the truss have the same cross section and material. (1) The system must have a vertical displacement at point B of less than 0.065 in, and a maximum absolute value of the normal stress less than 24 ksi in all the bars. Based on these two constraints, find the allowable load P. (2) Assuming P = 8k, find the stress at point p in the coordinate system given. (1) P= |(2) σ= k ksi A = 0.24 in² E=30000 ksi V = 0.29 point p A B YP 6 ft C P 8 ft
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![All bars in the truss have the same cross section and material.
(1) The system must have a vertical displacement at point B
of less than 0.065 in, and a maximum absolute value of the
normal stress less than 24 ksi in all the bars. Based on these
two constraints, find the allowable load P.
(2) Assuming P = 8k, find the stress
at point p in the coordinate
system given.
|(1) P=
(2) σ =
k
ksi
A = 0.24 in²
E = 30000 ksi
V = 0.29
point p
A
B
P
6 ft
C
P
8 ft](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe8988a1a-5625-4af8-94a1-38513bb2393c%2Fe33ed928-fe71-4079-9f73-ae0578c2a906%2F2bei29f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:All bars in the truss have the same cross section and material.
(1) The system must have a vertical displacement at point B
of less than 0.065 in, and a maximum absolute value of the
normal stress less than 24 ksi in all the bars. Based on these
two constraints, find the allowable load P.
(2) Assuming P = 8k, find the stress
at point p in the coordinate
system given.
|(1) P=
(2) σ =
k
ksi
A = 0.24 in²
E = 30000 ksi
V = 0.29
point p
A
B
P
6 ft
C
P
8 ft
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