All of these alkenes will form this alcohol. Figure 10 |BH3 сн, он CH3-CH- CH-CH, 2 H,02, NAOH A B CH, CH2 CH;=c-CH2-CH, CH3-C-CH,- CH, CH, CH,-c=CH-CH, CH, CH3-CH- CH=CH2 09:00 25°C Sunny 2021/11/19
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Q: 2. Give IUPAC names for the following alkanes: (a) CH3 (b) CH3CHCH,CH,CH, CH3CH2CCH3 (c) Haç CH3…
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- How do you convert 18.8 CP2/TM3 to YY2/ZW3? Use the folowing inequalities: 1CP=2.104 BX, *Bx=4 YY, 1TM=7.1088DD, 1DD=4.966ZW. When writing out the answer leave out the units.What volume of 95.0% alcohol by weight (density: 0.809g/cm^3) must be used to prepare150 cm^3 of 30.0% alcohol by weight (density: 0.957g/cm^3)Calculate The density of Freon CF2Cl3 at 30 C and 0.954
- An experiment was performed to look at how density changes when t he ratio of water and ethanol was changed. The following data was obtained: % Mass Ethano1.00 2.50 3.50 4.00 6.00 7.50 9.50 Density, g/mL0.9963 0.9936 0.9918 0.9910 0.9878 0.9855 0.9826 Use Excel or a similar spreadsheet program to plot these six data points and answer the following questions . a.What is the independent variable? b.What is the dependent variable? c.What is the equation of the best-‐fit line? d.What is the value of the coefficient of determination? e. According to the best-‐fit line, what should the density of pure water be (i.e. what is the density when % mass ethanol = 0.00)?Chemistry (i) For T = 298K ΔG° = -8.314 x 298 x ln (2.83x10-3) = 14.524 KJ/mol (ii) For T = 308.15K ΔG° = -8.314 x 308.15 x ln (9.619x10-3) = 11.891 KJ/mol (iii) For T = 318.15K ΔG° = -8.314 x 318.15 x ln (3.14x10-2) = 9.147 KJ/mol (iv) For T = 328.15K ΔG° = -8.314 x 328.15 x ln (8.82x10-2) = 6.621 KJ/mol (v) For T = 338.15K ΔG° = -8.314 x 338.15 x ln (2.42x10-1) = 3.990 KJ/mol Based on the measured ΔG° values, is this equilibrium spontaneous at room temperature? Which factor, entropy, or enthalpy, has the greater impact on spontaneity in this case? Explain your answers.Pheromones are compounds secreted by females of manyinsect species to attract mates. Typically, 1.0 × 10−8gof a pheromone is sufficient to reach all targeted maleswithin a radius of 0.50 mi. Calculate the density of thepheromone (in grams per liter) in a cylindrical air spacehaving a radius of 0.50 mi and a height of 40 ft (volumeof a cylinder of radius r and height h is πr2h).
- Given the following data forMass of test tube, beaker and cyclohexane = 100.17 gMass of test tube and beaker = 84.07 gFreezing point of cyclohexane = 6.59 oCMass of weighing paper + naphthalene =1.080 gMass of weighing paper = 0.928 gFreezing point solution = 5.11oCKf = 20.8oC/mDetermine the followinga. mass of cyclohexane in g (2 decimal places); _____b. mass of naphthalene in g (4 decimal places); _____c. freezing point depression (2 decimal places); _____d. molality of solution (3 significant figures); _____e. moles of naphthalene (3 significant figures); _____f. molar mass of naphthalene, experimentally (3 significant figures); _____g. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); ____Convert and use sig figs 254.3g to kghttps://vm.tiktok.com/ZMR9M8uA1/
- How do you convert 0.485L into mm using unit fractions?22. A 100g of water is mixed to 150g of alcohol (ρ = 0.76 g/cm3). Calculate the resulting density of the solution assuming that it is mixed completely.a. 0.8407g/cm3 b. 0.8379g/cm3 c. 0.8624g/cm3 d. 0.8153g/cm3Produce Water mass “X” is known to be a mixture of water masses “1”, “2”, and “3”. Using the data plotted below, calculate the composition of “X” (i.e. determine the fraction from each of the 3 water masses that makes up water mass X). Watermass#1– SF6 =25 S=33.5 Watermass#2– SF6 =75 S=32 Watermass#3– SF6 =50 S=36.5 Water mass X – SF6 =60 S= 34