Question
Aluminum chloride, AlCl3, is made by treating scrap aluminum with chlorine.

2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)

If you begin with 7.80 g Al and 3.11 g Cl2, identify the limiting reactant and determine what mass of the excess reactant remains when the reaction is completed?
 

 

 

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General Chemistry

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