The drawing below shows a mixture of molecules: key carbon O hydrogen nitrogen sulfur oxygen chlorine Suppose the following chemical reaction can take place in this mixture: CS (9)+302(g) CO,(g)+2SO2(g) Of which reactant are there the most initial moles? Enter its chemical formula: Of which reactant are there the least initial moles? Enter its chemical formula: Which reactant is the limiting reactant? Enter its chemical formula:

The drawing below shows a mixture of molecules: key carbon O hydrogen nitrogen sulfur oxygen chlorine Suppose the following chemical reaction can take place in this mixture: CS (9)+302(g) CO,(g)+2SO2(g) Of which reactant are there the most initial moles? Enter its chemical formula: Of which reactant are there the least initial moles? Enter its chemical formula: Which reactant is the limiting reactant? Enter its chemical formula:

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter2: Basic Statistical Analysis With Excel

Section: Chapter Questions

Problem 12P

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A. B. and C. already solved (https://www.bartleby.com/questions-and-answers/chemistry-question/a89691d6-2162-4677-b0cc-dc84fcceda08). Please answer E, F and GCircle in pencil in the image on th eirght cide of the diagram is a "2"( Pb(NO3)2 ).
https://cxp.cengage.com/contentservice/assets/owms01h/references/chemtables/gen_chem/eo.html ^ table image:
5.61 x 10^-12 is the ksp
https://www.youtube.com/watch?v=GpRqht0o4w4
You can use this as your reference: https://www.youtube.com/watch?v=2J2t5FRnMtM
Chemistry (i) For T = 298K ΔG° = -8.314 x 298 x ln (2.83x10-3) = 14.524 KJ/mol (ii) For T = 308.15K ΔG° = -8.314 x 308.15 x ln (9.619x10-3) = 11.891 KJ/mol (iii) For T = 318.15K ΔG° = -8.314 x 318.15 x ln (3.14x10-2) = 9.147 KJ/mol (iv) For T = 328.15K ΔG° = -8.314 x 328.15 x ln (8.82x10-2) = 6.621 KJ/mol (v) For T = 338.15K ΔG° = -8.314 x 338.15 x ln (2.42x10-1) = 3.990 KJ/mol Based on the measured ΔG° values, is this equilibrium spontaneous at room temperature? Which factor, entropy, or enthalpy, has the greater impact on spontaneity in this case? Explain your answers.
How do you convert 18.8 CP2/TM3 to YY2/ZW3? Use the folowing inequalities: 1CP=2.104 BX, *Bx=4 YY, 1TM=7.1088DD, 1DD=4.966ZW. When writing out the answer leave out the units.
Do I use the 2.9 as reference for my anserw?
H2SO3 = 0.2556 M, Ka1 = 1.6 x 10-2 , Ka2 = 6.4 x 10-8 NaOH = 0.3106 M please show all work all information needed is here
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ᴀ ꜱᴛᴇᴇʟ ᴛʀᴀɪɴ ʀᴀɪʟ ɪꜱ 400 ᴍᴇᴛᴇʀꜱ ʟᴏɴɢ, ɪɴ ᴍᴀʀᴄʜ ɪᴛ ɪꜱ -30 ᴅᴇɢʀᴇᴇ ᴄ ᴀɴᴅ 40 ᴅᴇɢʀᴇᴇ ᴄ ɪɴ ᴊᴜʟʏ. ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ᴄʜᴀɴɢᴇ ɪɴ ʟᴇɴɢᴛʜ ɪɴ ᴍᴍ? ᴋ ꜰᴏʀ ꜱᴛᴇᴇʟ = 11.7 x 10^-6 ᴍ/ᴍ-ᴄ
1. 500.0 mL 0.2 M KI2. 500.0 mL 0.2 M KCl3. 500.0 mL 0.1 M K2S2O84. 500.0 mL 0.1 M K2SO45. 500.0 mL 4.0 mM Na2S2O3 (from Na2S2O3∙5H2O)pls compelete the 2nd table given the data