Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al(OH)3(s) + 3 H2SO4(aq) Al2(SO.)3 (aq) + 6 H2O(1) a. Which is the limiting reactant when 0.500 mol Al(OH)3 and 0.500 mol H2SO, are allowed to react? b. How many moles of Al2(SO.)3 can form under these conditions? c. How many moles of the excess reactant remain after the completion of the reaction?

Chemistry: Principles and Reactions
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ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
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Chapter3: Mass Relations In Chemistry; Stoichiometry
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Aluminum hydroxide reacts with sulfuric acid as follows:
2 Al(OH)3(s) + 3 H2SO4(aq)
Al2(SO4)3 (aq) + 6 H20(1)
a. Which is the limiting reactant when 0.500 mol Al(OH)3 and 0.500 mol H2SO4 are allowed
to react?
b. How many moles of Al2(SO4)3 can form under these conditions?
c. How many moles of the excess reactant remain after the completion of the reaction?
Transcribed Image Text:Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al(OH)3(s) + 3 H2SO4(aq) Al2(SO4)3 (aq) + 6 H20(1) a. Which is the limiting reactant when 0.500 mol Al(OH)3 and 0.500 mol H2SO4 are allowed to react? b. How many moles of Al2(SO4)3 can form under these conditions? c. How many moles of the excess reactant remain after the completion of the reaction?
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