Ammonia gas can be prepared by the following reaction: CaO(s) + 2 NH4C1(s) →2 NH3(g) + H2O(g) + CaCl2 (s) If 480. g of CaO and 960. g of NH4CI are mixed, the theoretical yield of NH3 is 291 g. If only 147 g of NH3 is actually obtained, what is its percent yield?

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Chapter3: Stoichiometry
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Ammonia gas can be prepared by the following reaction:
CaO(s) + 2 NH4 Cl(s)2 NH3 (g) + H2O(g) + CaCl, (s)
If 480. g of CaO and 960. g of NH4C1 are mixed, the theoretical yield of NH3 is 291 g. If only 147 g of NH3 is actually obtained, what is its percent
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Transcribed Image Text:Ammonia gas can be prepared by the following reaction: CaO(s) + 2 NH4 Cl(s)2 NH3 (g) + H2O(g) + CaCl, (s) If 480. g of CaO and 960. g of NH4C1 are mixed, the theoretical yield of NH3 is 291 g. If only 147 g of NH3 is actually obtained, what is its percent yield? % Submit Answer Try Another Version 10 item attempts remaining
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