Ammonia gas can be prepared by the following reaction: CaO(s) +2 NH,Cl(s) → 2 NH3 (g) + H, 0(g) + CaCl2 (s) If 184 g of CaO and 368 g of NH,CI are mixed, the theoretical yield of NH; is 112 g. If only 20.4 g of NH, is actually obtained, what is its percent yield?

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.24PAE: 4.24 Ammonia gas can be prepared by the reaction CaO(s)+2NH4Cl(s)2NH3(g)+H2O(g)+CaCl2(s) If 112 g of...
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Ammonia gas can be prepared by the following reaction:
CaO(s) +2 NH,Cl(s) → 2 NH3 (g) + H, 0(g) + CaCl2 (s)
If 184 g of CaO and 368 g of NH,CI are mixed, the theoretical yield of NH; is 112 g. If only 20.4 g of NH, is actually obtained, what is its percent yield?
Transcribed Image Text:Ammonia gas can be prepared by the following reaction: CaO(s) +2 NH,Cl(s) → 2 NH3 (g) + H, 0(g) + CaCl2 (s) If 184 g of CaO and 368 g of NH,CI are mixed, the theoretical yield of NH; is 112 g. If only 20.4 g of NH, is actually obtained, what is its percent yield?
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