4.1.4 An accounting office has 6 incoming telephone lines. The probability distribution of the number of busylines, X, is as follows:12345TotalP(X = x;)0.050.120.170.310.190.150.0111. Use the random variable notation to express symbolically each of the following:V An event in which the number of busy lines is exactly 4.v The probability of an event in which the number of busy lines is exactly 1.The probability of an event in which the number of busy lines is exactly 4is equal to 0.19.2. Use the above probability distribution table to find the following:а. Р(1 < X < 3) -(Round the answer to 2 decimals)b. P(0 < X < 3) =(Round the answer to 2 decimals)с. Р(X < 5) %3(Round the answer to 2 decimals)

Given: To find: To find P1<X<3, P0<X<3, and PX≤5 from the given probability…

An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy lines, X, is as follows: 1 2 4 Total P(X = x;) 0.05 0.12 0.17 0.31 0.19 0.15 0.01 1 1. Use the random variable notation to express symbolically each of the following: An event in which the number of busy lines is exactly 4. The probability of an event in which the number of busy lines is exactly 1. The probability of an event in which the number of busy lines is exactly 4 is equal to 0.19. 2. Use the above probability distribution table to find the following: a. P(1 < X < 3) = (Round the answer to 2 decimals) %3D b. P(0 < X < 3) = c. P(X < 5) = (Round the answer to 2 decimals) %3D (Round the answer to 2 decimals)

An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy lines, X, is as follows: 1 2 4 Total P(X = x;) 0.05 0.12 0.17 0.31 0.19 0.15 0.01 1 1. Use the random variable notation to express symbolically each of the following: An event in which the number of busy lines is exactly 4. The probability of an event in which the number of busy lines is exactly 1. The probability of an event in which the number of busy lines is exactly 4 is equal to 0.19. 2. Use the above probability distribution table to find the following: a. P(1 < X < 3) = (Round the answer to 2 decimals) %3D b. P(0 < X < 3) = c. P(X < 5) = (Round the answer to 2 decimals) %3D (Round the answer to 2 decimals)

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter9: Counting And Probability

Section9.3: Binomial Probability

Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...

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