Thermodynamic An air-standard power cycle with constant specific heats is executed in a closed systemand is composed of the following five processes. Assuming constant specific heats atroom temperature, calculate the mean effective pressure of the cycle, in kPa.Properties of air: C,=0.718 kJ/(kgK), C,=1.005 kJ/(kgK), R=0.287 kJ/(kgK), k=1.4Process 1-2: Isentropic compression from P1=110 kPa to P2. The minimumtemperature of the cycle is T1=299 K. The compression ratio of the cycle is 8.8.Process 2-3: Heat addition of q23=900 kJ/kg to the cycle at constant volume.Process 3-4: Isentropic expansion from P3 to P4=221 kPaProcess 4-5: Heat rejection of q45 from the cycle at constant volume.Process 5-1: Heat rejection of q51 from the cycle at constant pressure.

Air m = 1Kgp1 = 110KPa1T1 = 299Kcompression ratio (r) = v1v2

An air-standard power cycle with constant specific heats is executed in a closed system and is composed of the following five processes. Assuming constant specific heats at room temperature, calculate the mean effective pressure of the cycle, in kPa. Properties of air: C,=0.718 kJ/(kgK), C,=1.005 kJ/(kgK), R=0.287 kJ/(kgK), k=1.4 Process 1-2: Isentropic compression from Pz=110 kPa to P2. The minimum temperature of the cycle is T1=299 K. The compression ratio of the cycle is 8.8. Process 2-3: Heat addition of q23=900 kJ/kg to the cycle at constant volume. Process 3-4: Isentropic expansion from P3 to P4=221 kPa Process 4-5: Heat rejection of q45 from the cycle at constant volume. Process 5-1: Heat rejection of q51 from the cycle at constant pressure.

An air-standard power cycle with constant specific heats is executed in a closed system and is composed of the following five processes. Assuming constant specific heats at room temperature, calculate the mean effective pressure of the cycle, in kPa. Properties of air: C,=0.718 kJ/(kgK), C,=1.005 kJ/(kgK), R=0.287 kJ/(kgK), k=1.4 Process 1-2: Isentropic compression from Pz=110 kPa to P2. The minimum temperature of the cycle is T1=299 K. The compression ratio of the cycle is 8.8. Process 2-3: Heat addition of q23=900 kJ/kg to the cycle at constant volume. Process 3-4: Isentropic expansion from P3 to P4=221 kPa Process 4-5: Heat rejection of q45 from the cycle at constant volume. Process 5-1: Heat rejection of q51 from the cycle at constant pressure.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The compression ratio of an air-standard dual cycle is 10:1, it begins at 120 kPa and 300 K, and the total heat intake of the cycle has a value of 275 kJ/kg. If this heat intake at constant volume is three-fifth of the total, determine the following: V1, P2, V2, T2, T3, P3, T4, V4, T5, heat rejected, net work, volume displacement and mean effective pressure.
An air-standard cycle with variable specific heats is executed in a closed system with 0.0045 kg of air and consists of the following three processes: 1–2 v = Constant heat addition from 95 kPa and 17°C to 380 kPa 2–3 Isentropic expansion to 95 kPa 3–1 P = Constant heat rejection to initial state Use data from tables. Calculate the thermal efficiency % ? Hint : The answer should be a percentage
An air-standard dual cycle has a compression ratio of 14. At the beginning of compression, p1 = 14.5 lbf/in.2, V1 = 0.5 ft3, and T1 = 50°F. The pressure doubles during the constant-volume heat addition process.For a maximum cycle temperature of 3000°R, determine:(a) the heat addition to the cycle, in Btu.(b) the net work of the cycle, in Btu.(c) the percent thermal efficiency.(d) the mean effective pressure, in lbf/in.2
2. An air-standard Otto cycle has a compression ratio of 9. At the beginning of compression, P1= 100 kPa and T1= 300 K. The heat addition per unit mass of air is 1350 kJ/kg. Determine (a) the net work, in kJ per kg of air. (b) the thermal efficiency of the cycle. (c) the mean effective pressure, in kPa. ((d) the maximum temperature in the cycle, in K..
PART D only A gas-turbine power generator operates on an ideal air-standard Brayton cycle 1 → 2 → 3 → 4 shown in Fig. 1. The gas temperatures at the compressor inlet, compressor exit, and turbine inlet are T1 = 300 K, T2 = 600 K, and T3 = 1200 K, respectively. Solve PART D below using the variable specific heat assumption PART D - Evaluate the thermal efficiency η of the cycle and the back work ratio rBW = wC/wT.
9.1 An air-standard Otto cycle has a compression ratio of 8.5. Atthe beginning of compression, p1= 100 kPa and T1 = 300 K.The heat addition per unit mass of air is 1400 kJ/kg. Determine(a) the net work, in kJ per kg of air.(b) the thermal efficiency of the cycle.(c) the mean effective pressure, in kPa.(d) the maximum temperature in the cycle, in K. 9.2 Solve Problem 9.1 on a cold air-standard basis with specificheats evaluated at 300 K. 9.3 At the beginning of the compression process of an air standard Ottocycle, p1 1 bar, T1 290 K, V1 400 cm3. The maximum temperature in the cycle is 2200 K and the compression ratio is 8. Determine(a) the heat addition, in kJ.(b) the net work, in kJ.(c) the thermal efficiency.(d) the mean effective pressure, in bar. 9.4 Solve Problem 9.3 on a cold air-standard basis with specific heatsevaluated at 300 K.
An air-standard Otto cycle has a compression ratio of 9. At the beginning of compression, P1 = 100 kPa and T1 = 300 K. The heat addition per unit mass of air is 1350 kJ/kg. Determine: a) the net work, in kJ per kg of air b) the thermal efficiency of the cycle c) the mean effective pressure, in kPa
Thermodynamics Answer the following questions with complete solutions. write legibly An engine operates with air on the cycle shown with isentropic processes 1 - 2 and 3 - 4, and constant volume processes at 2 - 3 and 4 - 1. If the compression ratio (r) is 12, the minimum pressure is 200 kPa, and the maximum pressure is 10 MPa, determine the net cycle work (Wcycle) in terms of the final volume of isentropic compression process (V2). (Note: r = V1/V2 = V4/V3).
At the beginning of the compression process in an air standard dual cycle, P1 = 1 bar and T1 = 300 K. Qin is 1000 kJ/kg.Consider compression ratio ranging from 10 to 20. Determine the work net
Hello im having some troubles with this question An air-standard cycle is executed within a closed piston–cylinder system and consists of three processes as follows: 1→2: constant-volume head addition from 100 kPa and 27°C to 850 kPa 2→3: isothermal expansion until ?3 =7?2 3→1: constant-pressure heat rejection to the initial state. Assuming that air has constant properties with Cv = 0.718 kJ/kg·K, Cp = 1.005 kJ/kg·K, γ = 1.4 and R=0.287 kJ/kg.K (a) Sketch the T-S and P-V diagram of the cycle (b) Determine the ratio of the compression work to the expansion work (c) Calculate the cycle thermal efficiency
At the beginning of the compression process in an air standard dual cycle, P1 = 1 bar and T1 = 300 K. Qin is 1000 kJ/kg.Consider compression ratio ranging from 10 to 20. Determine v1 and v2
3The rate of heat addition to an ideal air-standard Brayton cycle is 1.0 x 107 Btu/h. The pressure ratio for the cycle is 12 and the minimum and maximum temperatures are 520°R and 2800°R, respectively.Determine:(a) the percent thermal efficiency of the cycle.(b) the mass flow rate of air, in lb/h.(c) the net power developed by the cycle, in hp.