An annual championship event is the most widely watched sporting event in a country each year. In recent years, there has been a great deal of interest in the ads that appear during the game. These ads vary in length with most lasting 30 seconds or 60 seconds. The accompanying data represent the ad length and ad scores from a recent championship. Assuming that the population variances from the 30-second ads and the 60-second ads are equal, is there evidence of a difference in the mean score between the two types of ads? Use α=0.02. Let μ1 be the mean score for the 30-second ads and μ2 be the mean score for the 60-second ads. Determine the hypotheses. Choose the correct answer below. A. H0:μ1=μ2 H1:μ1≠μ2 B. H0:μ1≠μ2 H1:μ1=μ2 C. H0:μ1≤μ2 H1:μ1>μ2 D. H0: μ1≥μ2 H1: μ1<μ2 t-stat= p-value= Hint from Tim: complete part B first...then come back to this part...if p < α, then reject Ho... __A__ H0. There is __B__ is evidence that the mean scores differ. A: do not reject or reject B: insufficient or suffcient Assuming that the population variances from both types of ads are equal, construct and interpret a 98% confidence interval estimate of the difference between the population mean score of the two types of ads. The confidence interval is __ ≤μ1−μ2≤ __. Interpret the confidence interval. Choose the correct answer below. A. One can say with 2% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads is smaller than the lower bound. B. One can say with 2% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads is larger than the upper bound. C. One can say with 98% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads falls outside this interval. D. One can say with 98% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads falls in this interval.

An annual championship event is the most widely watched sporting event in a country each year. In recent years, there has been a great deal of interest in the ads that appear during the game. These ads vary in length with most lasting 30 seconds or 60 seconds. The accompanying data represent the ad length and ad scores from a recent championship. Assuming that the population variances from the 30-second ads and the 60-second ads are equal, is there evidence of a difference in the mean score between the two types of ads? Use α=0.02. Let μ1 be the mean score for the 30-second ads and μ2 be the mean score for the 60-second ads. Determine the hypotheses. Choose the correct answer below. A. H0:μ1=μ2 H1:μ1≠μ2 B. H0:μ1≠μ2 H1:μ1=μ2 C. H0:μ1≤μ2 H1:μ1>μ2 D. H0: μ1≥μ2 H1: μ1<μ2 t-stat= p-value= Hint from Tim: complete part B first...then come back to this part...if p < α, then reject Ho... A H0. There is B is evidence that the mean scores differ. A: do not reject or reject B: insufficient or suffcient Assuming that the population variances from both types of ads are equal, construct and interpret a 98% confidence interval estimate of the difference between the population mean score of the two types of ads. The confidence interval is ≤μ1−μ2≤ . Interpret the confidence interval. Choose the correct answer below. A. One can say with 2% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads is smaller than the lower bound. B. One can say with 2% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads is larger than the upper bound. C. One can say with 98% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads falls outside this interval. D. One can say with 98% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads falls in this interval.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.3: Measures Of Spread

Problem 26PFA

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Question

Assuming that the population variances from the 30-second ads and the 60-second ads are equal, is there evidence of a difference in the mean score between the two types of ads? Use

α=0.02.

Let μ1 be the mean score for the 30-second ads and μ2 be the mean score for the 60-second ads. Determine the hypotheses. Choose the correct answer below.

H0:μ1=μ2

H1:μ1≠μ2

H0:μ1≠μ2

H1:μ1=μ2

H0:μ1≤μ2

H1:μ1>μ2

H0: μ1≥μ2

H1: μ1<μ2

t-stat=

p-value=

Hint from Tim: complete part B first...then come back to this part...if p < α, then reject Ho...

__A__ H0. There is __B__ is evidence that the mean scores differ.

A: do not reject or reject

B: insufficient or suffcient

Assuming that the population variances from both types of ads are equal, construct and interpret a 98% confidence interval estimate of the difference between the population mean score of the two types of ads.

The confidence interval is

__ ≤μ1−μ2≤ __.

Interpret the confidence interval. Choose the correct answer below.

One can say with 2% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads is smaller than the lower bound.

One can say with 2% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads is larger than the upper bound.

One can say with 98% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads falls outside this interval.

One can say with 98% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads falls in this interval.

w!
An annual championship event is the most widely wa
been a great deal of interest in the ads that appear d
or 60 seconds. The accompanying data represent the
(a) through (c).
30-Second Ads 60-Second Ads
40 25 35 36 47 70 57 51 54 50
42 22 31 51 51 20 31 33 42 64
a. Assuming that the population variances from the 30
difference in the mean score between the two types o
Let u, be the mean score for the 30-second ads and
hypotheses. Choose the correct answer below.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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