An annual championship event is the most widely watched sporting event in a country each year. In recent years, there has been a great deal of interest in the ads that appear during the game. These ads vary in length with most lasting 30 seconds or 60 seconds. The accompanying data represent the ad length and ad scores from a recent championship. Complete parts (a) through (c). Assuming that the population variances from the 30-second ads and the 60-second ads are equal, is there evidence of a difference in the mean score between the two types of ads? Useα=0.05. Let μ1 be the mean score for the 30-second ads and μ2 be the mean score for the 60-second ads. Determine the hypotheses. Choose the correct answer below. A. H0: μ1≠μ2 H1: μ1=μ2 B. H0: μ1=μ2 H1: μ1≠μ2 C. H0: μ1≥μ2 H1: μ1μ2 tSTAT=___ Choose the correct conclusion below.___A___ H0. There is __B___ evidence that the mean scores differ. A: Do not reject or rejectB: insufficient or sufficient p-value=____ Assuming that the population variances from both types of ads are equal, construct, and interpret a 95% confidence interval estimate of the difference between the population means the score of the two types of ads. The confidence interval is __ ≤μ1−μ2≤ __.(Type an integer or decimal rounded to two decimal places as needed.) Interpret the confidence interval. Choose the correct answer below. A. One can say with 95% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads falls in this interval. B. One can say with 5% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads is smaller than the lower bound. C. One can say with 5% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads is larger than the upper bound. D. One can say with 95% confidence that the difference between the population mean score of the 30-second ads and the 60-second ads falls outside this interval. Instructor-created questionAn annual championship event is the most widely watchedseconds or 60 seconds. The accompanying data represent30-Second Ads 60-Second Ads47 20 31 30 47 62 57 52 55 5046 21 35 54 53 29 30 36 42 65a. Assuming that the population variances from the 30-secolLet H1be the mean score for the 30-second ads and u2 be tOA. Ho: H1 #H2H:H1=H2OC. Ho: H1Z H2

Question

An annual championship event is the most widely watched sporting event in a country each year. In recent​ years, there has been a great deal of interest in the ads that appear during the game. These ads vary in length with most lasting 30 seconds or 60 seconds. The accompanying data represent the ad length and ad scores from a recent championship. Complete parts​ (a) through​ (c). Assuming that the population variances from the​ 30-second ads and the​ 60-second ads are​ equal, is there evidence of a difference in the mean score between the two types of​ ads? Useα=0.05. Let μ1 be the mean score for the​ 30-second ads and μ2 be the mean score for the​ 60-second ads. Determine the hypotheses. Choose the correct answer below. A. H0​: μ1≠μ2     H1​: μ1=μ2 B. H0​: μ1=μ2     H1​: μ1≠μ2 C. H0​: μ1≥μ2     H1​: μ1<μ2 D. H0​:μ1≤μ2     H1​: μ1>μ2 tSTAT=___ Choose the correct conclusion below.___A___ H0. There is __B___ evidence that the mean scores differ. A: Do not reject or rejectB: insufficient or sufficient  p-value=____ Assuming that the population variances from both types of ads are​ equal, construct, and interpret a 95​% confidence interval estimate of the difference between the population means the score of the two types of ads. The confidence interval is __ ≤μ1−μ2≤ __.​(Type an integer or decimal rounded to two decimal places as​ needed.) Interpret the confidence interval. Choose the correct answer below.  A. One can say with 95​% confidence that the difference between the population mean score of the​ 30-second ads and the​ 60-second ads falls in this interval. B. One can say with 5​% confidence that the difference between the population mean score of the​ 30-second ads and the​ 60-second ads is smaller than the lower bound. C. One can say with 5​% confidence that the difference between the population mean score of the​ 30-second ads and the​ 60-second ads is larger than the upper bound. D. One can say with 95​% confidence that the difference between the population mean score of the​ 30-second ads and the​ 60-second ads falls outside this interval. Instructor-created questionAn annual championship event is the most widely watchedseconds or 60 seconds. The accompanying data represent30-Second Ads 60-Second Ads47 20 31 30 47 62 57 52 55 5046 21 35 54 53 29 30 36 42 65a. Assuming that the population variances from the 30-secolLet H1be the mean score for the 30-second ads and u2 be tOA. Ho: H1 #H2H:H1=H2OC. Ho: H1Z H2

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