perform this exercise in minitab 8-56. + An article in the Australian Journal of AgriculturalResearch [“Non-Starch Polysaccharides and Broiler Perfor-mance on Diets Containing Soyabean Meal as the Sole ProteinConcentrate" (1993, Vol. 44(8), pp. 1483–1499)] determinedthat the essential amino acid (Lysine) composition level of soy-bean meals is as shown here (g/kg):22.224.720.926.027.024.826.523.825.623.9(a) Construct a 99% two-sided confidence interval for o?.(b) Calculate a 99% lower confidence bound for o.(c) Calculate a 90% lower confidence bound for o.(d) Compare the intervals that you have computed. a) 99% two-sided confidence interval on on = 10s = 1.913 x00s 9 = 23.59 and xo 9959 = 1.739(1.913)?so?9(1.913)?23.591.731.396 s o? s 19.038b) 99% lower confidence bound for oFor a = 0.01 and n=10, x- - Xo019 =21.679(1.913)?so?21.671.5199 so?c) 90% lower confidence bound for o?For a = 0.1 and n = 10, Xan-19(1.913)Xó19 =14.68=so?14.682.2436 so?1.498 s od) The lower confidence bound of the 99% two-sided interval is less than the one-sided interval. The lowerconfidence bound for o is in part (c) is greater because the confidence is lower.

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A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose that in a sample of 4876customers at a food store, 2654food shop more than once a week. Find a 90% confidence interval for the population proportion of customers who shop more than once a week. Interpret your answer. b) A claim is made that 52% of all customers at a food store shop more than once a week. Using the results from part (a) of this problem, would this claim be valid or invalid?
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 550 randomly selected Americans surveyed, 385 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between ? and ?. b. If many groups of 550 randomly selected Americans were surveyed, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about ? percent will not contain the true population proportion.
"Trydint" bubble-gum company claims that 4 out of 10 people prefer their gum to "Eklypse". Test their claim at the 95 confidence level.The null and alternative hypothesis in symbols would be: H0:μ≥0.4H0:μ≥0.4H1:μ<0.4H1:μ<0.4 H0:p=0.4H0:p=0.4H1:p≠0.4H1:p≠0.4 H0:p≤0.4H0:p≤0.4H1:p>0.4H1:p>0.4 H0:p≥0.4H0:p≥0.4H1:p<0.4H1:p<0.4 H0:μ≤0.4H0:μ≤0.4H1:μ>0.4H1:μ>0.4 H0:μ=0.4H0:μ=0.4H1:μ≠0.4H1:μ≠0.4 The null hypothesis in words would be: The average of people that prefer Trydint gum is 0.4. The proportion of people in a sample that prefers Trydint gum is 0.4. The proportion of all people that prefer Trydint gum is less than 0.4. The proportion of all people that prefer Trydint gum is greater than 0.4. The proportion of people in a sample that prefer Trydint gum is not 0.4 The average of people that prefer Trydint gum is not 0.4. The proportion of all people that prefer Trydint gum is 0.4 Based on a sample of 130 people, 49 said they prefer "Trydint" gum to…
"Trydint" bubble-gum company claims that 4 out of 10 people prefer their gum to "Eklypse". Test their claim at the 99 confidence level.The null and alternative hypothesis in symbols would be: H0:p≤0.4H0:p≤0.4H1:p>0.4H1:p>0.4 H0:μ≤0.4H0:μ≤0.4H1:μ>0.4H1:μ>0.4 H0:p≥0.4H0:p≥0.4H1:p<0.4H1:p<0.4 H0:p=0.4H0:p=0.4H1:p≠0.4H1:p≠0.4 H0:μ≥0.4H0:μ≥0.4H1:μ<0.4H1:μ<0.4 H0:μ=0.4H0:μ=0.4H1:μ≠0.4H1:μ≠0.4 The null hypothesis in words would be: The proportion of all people that prefer Trydint gum is 0.4 The proportion of people in a sample that prefer Trydint gum is not 0.4 The proportion of people in a sample that prefers Trydint gum is 0.4. The proportion of all people that prefer Trydint gum is less than 0.4. The average of people that prefer Trydint gum is not 0.4. The proportion of all people that prefer Trydint gum is greater than 0.4. The average of people that prefer Trydint gum is 0.4. Based on a sample of 110 people, 19 said they prefer "Trydint" gum to…
A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 598 randomly selected Americans surveyed, 384 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 99% confidence the proportion of all Americans who favor the new Green initiative is between ? and ? b. b. If many groups of 598 randomly selected Americans were surveyed, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about ? percent will not contain the true population proportion.
A smart phone manufacturer is interested in constructing a 90% confidence interval for the proportion of smart phones that break before the warranty expires. 90 of the 1595 randomly selected smart phones broke before the warranty expired. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all smart phones that break before the warranty expires is between ? and ? b. If many groups of 1595 randomly selected smart phones are selected, then a different confidence interval would be produced for each group. About ?percent of these confidence intervals will contain the true population proportion of all smart phones that break before the warranty expires and about ? percent will not contain the true population proportion.
A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 506 randomly selected Americans surveyed, 376 were in favor of the initiative. Round answers to 2 decimal places where possible.a. With 99% confidence the proportion of all Americans who favor the new Green initiative is between and . b. If many groups of 506 randomly selected Americans were surveyed, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about ? percent will not contain the true population proportion.
"Trydint" bubble-gum company claims that 5 out of 10 people prefer their gum to "Eklypse". Test their claim at the 99 confidence level. The null and alternative hypothesis in symbols would be: H0:μ≥0.5H0:μ≥0.5 H1:μ<0.5H1:μ<0.5 H0:p≥0.5H0:p≥0.5 H1:p<0.5H1:p<0.5 H0:μ≤0.5H0:μ≤0.5 H1:μ>0.5H1:μ>0.5 H0:p=0.5H0:p=0.5 H1:p≠0.5H1:p≠0.5 H0:p≤0.5H0:p≤0.5 H1:p>0.5H1:p>0.5 H0:μ=0.5H0:μ=0.5 H1:μ≠0.5H1:μ≠0.5 The null hypothesis in words would be: The proportion of all people that prefer Trydint gum is 0.5The proportion of all people that prefer Trydint gum is greater than 0.5.The proportion of all people that prefer Trydint gum is less than 0.5.The proportion of people in a sample that prefer Trydint gum is not 0.5The average of people that prefer Trydint gum is 0.5.The average of people that prefer Trydint gum is not 0.5.The proportion of people in a sample that prefers Trydint gum is 0.5. Based on a sample of 290 people, 121 said they prefer "Trydint" gum to "Eklypse".…
"Trydint" bubble-gum company claims that 7 out of 10 people prefer their gum to "Eklypse". Test their claim at the 90 confidence level.The null and alternative hypothesis in symbols would be: H0:μ≥0.7H0:μ≥0.7H1:μ<0.7H1:μ<0.7 H0:p≤0.7H0:p≤0.7H1:p>0.7H1:p>0.7 H0:μ=0.7H0:μ=0.7H1:μ≠0.7H1:μ≠0.7 H0:p=0.7H0:p=0.7H1:p≠0.7H1:p≠0.7 H0:μ≤0.7H0:μ≤0.7H1:μ>0.7H1:μ>0.7 H0:p≥0.7H0:p≥0.7H1:p<0.7H1:p<0.7 The null hypothesis in words would be: The proportion of people in a sample that prefer Trydint gum is not 0.7 The proportion of all people that prefer Trydint gum is 0.7 The proportion of people in a sample that prefers Trydint gum is 0.7. The proportion of all people that prefer Trydint gum is greater than 0.7. The average of people that prefer Trydint gum is 0.7. The average of people that prefer Trydint gum is not 0.7. The proportion of all people that prefer Trydint gum is less than 0.7. Based on a sample of 200 people, 112 said they prefer "Trydint" gum to…
"Trydint" bubble-gum company claims that 9 out of 10 people prefer their gum to "Eklypse". Test their claim at the 90 confidence level.The null and alternative hypothesis in symbols would be: H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ≤0.9H0:μ≤0.9H1:μ>0.9H1:μ>0.9 H0:μ≥0.9H0:μ≥0.9H1:μ<0.9H1:μ<0.9 H0:p≤0.9H0:p≤0.9H1:p>0.9H1:p>0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:p≥0.9H0:p≥0.9H1:p<0.9H1:p<0.9 The null hypothesis in words would be: The proportion of all people that prefer Trydint gum is greater than 0.9. The proportion of all people that prefer Trydint gum is 0.9 The proportion of people in a sample that prefers Trydint gum is 0.9. The average of people that prefer Trydint gum is not 0.9. The proportion of people in a sample that prefer Trydint gum is not 0.9 The proportion of all people that prefer Trydint gum is less than 0.9. The average of people that prefer Trydint gum is 0.9. Based on a sample of 390 people, 341 said they prefer "Trydint" gum to…
1.A smart phone manufacturer is interested in constructing a 95% confidence interval for the proportion of smart phones that break before the warranty expires. 95 of the 1608 randomly selected smart phones broke before the warranty expired. Round answers to 4 decimal places where possible. a. With 95% confidence the proportion of all smart phones that break before the warranty expires is between and . b. If many groups of 1608 randomly selected smart phones are selected, then a different confidence interval would be produced for each group. About percent of these confidence intervals will contain the true population proportion of all smart phones that break before the warranty expires and about percent will not contain the true population proportion. 2.You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately p = 0.82. You would like to be 96% confident that your esimate is within 2% of the…
ou are interested in constructing a 90% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 352 randomly selected caterpillars observed, 55 lived to become butterflies. Round answers to 5 decimal places where possible. a. With 90% confidence the proportion of all caterpillars that lived to become a butterfly is between ?and .? b. If many groups of 352 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about ? percent will not contain the true population proportion.

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An article in the Australian Journal of Agricultural [“Non-Starch Polysaccharides and Broiler Perfor- Diets Containing Soyabean Meal as the Sole Protein te" (1993, Vol. 44(8), pp. 1483–1499)] determined sential amino acid (Lysine) composition level of soy- s is as shown here (g/kg):