An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mg travels to the right with speed vR. Show the velocity of piece B in terms of ma mg and VA- Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf =0 Substituting the expression for momentum results to mgv mAV = 0 Deriving the expression for the velocity of piece B results to =(ma/m VA

Modern Physics
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Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
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Chapter1: Relativity I
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An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mp travels to the right with speed vp. Show the
velocity of piece B in terms of mA: mB and VA
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
PBf + PAf = 0
Substituting the expression for momentum results to
mBv
mav
= 0
Deriving the expression for the velocity of piece B results to
=(ma/m
VA
Transcribed Image Text:An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mp travels to the right with speed vp. Show the velocity of piece B in terms of mA: mB and VA Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf = 0 Substituting the expression for momentum results to mBv mav = 0 Deriving the expression for the velocity of piece B results to =(ma/m VA
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