An engineer calculated the AW values shown for retaining a presently owned machine additional years. A challenger has an ESL of 4 years with AW = $-60,000 per year. Assuming all future costs remain the same, when should the company replace the defender? The MARR is 12% per year. Assume used machines like the one presently owned will always be available. AW of Defender, 24 -77,000 -63,000 -58,000 Years Retained -64,000 -70,000 345

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An engineer calculated the AW values shown for retaining a presently owned
machine additional years.
A challenger has an ESL of 4 years with AW = $-60,000 per year.
Assuming all future costs remain the same, when should the company replace the
defender?
The MARR is 12% per year. Assume used machines like the one presently owned will
always be available.
AW of Defender,
24
-77,000
-63,000
Years Retained
1
12
-58,000
-64,000
-70,000
13
4
a) at year 5
b) at vear 2
always be available.
AW of Defender,
2$
|-77,000
-63,000
-58,000
-64,000
-70,000
Years Retained
3
4
15
O a) at year 5
b) at year 2
c) at year 1
d) at year 4
e) at year 3
Transcribed Image Text:An engineer calculated the AW values shown for retaining a presently owned machine additional years. A challenger has an ESL of 4 years with AW = $-60,000 per year. Assuming all future costs remain the same, when should the company replace the defender? The MARR is 12% per year. Assume used machines like the one presently owned will always be available. AW of Defender, 24 -77,000 -63,000 Years Retained 1 12 -58,000 -64,000 -70,000 13 4 a) at year 5 b) at vear 2 always be available. AW of Defender, 2$ |-77,000 -63,000 -58,000 -64,000 -70,000 Years Retained 3 4 15 O a) at year 5 b) at year 2 c) at year 1 d) at year 4 e) at year 3
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