Question
Asked Nov 24, 2019
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An equilibrium mixture of the following reaction was found to have [SO3]= 0.441 M and [O2]= 0.115 M at 600 ∘C.

What is the concentration of SO2?
2SO2(g)+O2(g)⇌2SO3(g)
Keq= 4.14 at 600 ∘C

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Expert Answer

Step 1

The Equilibrium constant for a given reaction can be defined as the relation between the reactants and the products that have reached equilibrium to some specific unit. For a hypothetical reaction, say,

aА+bв —
eСС+dD
[C]
К
[АJ [В
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aА+bв — eСС+dD [C] К [АJ [В

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Step 2

The given reaction is as follows:

2SO, (g)+O2(g)
2SO, (g)
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2SO, (g)+O2(g) 2SO, (g)

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Step 3

The concentration of SO3 gas is given to be 0.441 M.

The concentration of O2 gas is given to be 0.115 M.

The equilibrium constant at a give...

[SO,j2
К
[SO, [O,
(0.441)
4.14
[SO,F (0.115)
(0.441)
[SO,j2
4.14x0.115
[So, 0.4084
SO,0.639M
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[SO,j2 К [SO, [O, (0.441) 4.14 [SO,F (0.115) (0.441) [SO,j2 4.14x0.115 [So, 0.4084 SO,0.639M

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