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An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $ 413,$456 , $408 , $237 . Compute the range, sample variance, and sample standard deviation cost of repair.The range is $s2  = (Round to the nearest whole number as needed.)s = $(Round to two decimal places as needed.)

Question

An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $ 413,
$456 , $408 , $237 . Compute the range, sample variance, and sample standard deviation cost of repair.

The range is $


s
(Round to the nearest whole number as needed.)


s = $
(Round to two decimal places as needed.)

check_circleAnswer
Step 1

Range:

The range is the difference between the largest and smallest values of the data distribution.

Step 2

The range “$219” is obtained as follows:

Range Largest value - Smallest value
$456 $237
-$219
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Range Largest value - Smallest value $456 $237 -$219

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Step 3

Sample variance (s2):

Let x denotes cost of ...

Number
1
413
170,569
207,936
166,464
56,169
601,138
2
456
408
3
237
4
Total
1,514
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Number 1 413 170,569 207,936 166,464 56,169 601,138 2 456 408 3 237 4 Total 1,514

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