An open feedwater heater is a direct-contact heat exchanger used in vapor power plants. Shown in the figure below arefeedwater heater with H20operating data for an open31 °Cas the working fluid operating at steady state, where T1P2=3 bar= 0.92+2P3 3 barSaturated liquidm380 kg/sT, PT=3 barOpenfeedwater3heaterIgnoring stray heat transfer from the outside of the heat exchanger to its surroundings and kinetic and potential energy effects, determine the rate ofentropy production, in kW/K.

Obtain the value of enthalpy and entropy corresponding to pressure 3 bar and temperature 31 deg…

Answered: An open feedwater heater is a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Steam power plant shown in figure isoperating at steady state with water as the workingfluid. The mass flow rate of the water circulatingthrough the components is 50 kg/s. Determine:a) thermal efficiency of the actual cycleb) Carnot cycle efficiency (justify anyassumptions you make in calculating ηCarnot)c) isentropic turbine efficiencyd) isentropic pump efficiencye) mass flow rate of the cooling water, in kg/s.f) rates of entropy production, each in kW/K, forthe turbine and steam generator
For the NH3/H2O cycle the following relationship give the solution flow rate per unit refrigeration rate: WFS_A * X - WFS_G(X-1) = 1 whereWFS_A = mass fraction of NH3 in solution form the absorberWFS_G = mass fraction of NH3 in solution from the generator X-1 =mass of solution from the generator per unit mass of refrigerant flowFor large systems, a reasonable pressure drop between the evaporator and absorber is 1.5 psiConsider a large NH3/H2O plant operating per the schematic below: Known/given:i. Refrigeration load = 500 tonsii. Evaporator temperature (state point 10) = 41.1 Fiii. Evaporator pressure (state point 10) = 75 psiaiv. Absorber pressure (state point 11) = 73.5 psia (per rule of thumb above regarding pressure drop between the evaporator and absorber)v. Strong aqua solution temperature (state point 3) = 105 Fvi. Condenser temperature (state point 8) = 100 Fvii. Condenser and tower pressure (state point 7) = 211.9 psiaviii. Concentration split, WFS_G - WFS_A =6% by weight…
I want to know how this problem can be done using mollier-chart please let me know what I did wrong in the Attached mollier-chart picture so the solution didn't come out to be right. The problem A steam power plant, operating with one regenerative feed water heating at the initial steam conditions of P=35 bar, T=440°C, exhaust pressure at 0.04 bar. Steam is bled from the turbine for feed water heating at a pressure of 1.226 bar.Determine1-Specific heat consumption2- Thermal efficiency of the cycle3- Thermal efficiency of the cycle neglecting regeneration
A counter flow heat exchanger operates in a stable state, ignoring kinetic and potential effects. Liquid water enters at 15°C and leaves at 23°C, neglecting the change in pressure on the liquid side. On the other side, the refrigerant R-134a enters at 12 bar, 90°C and 150 kg/h, and the outlet condition is 12 bar, 28°C. The heat from the outer surface of the heat exchanger will be neglected. a) Determine the mass flow rate of the liquid water flow in kg/h. b) Determine the entropy production of the heat exchanger in kW/K
A counter flow heat exchanger operates in a stable state, ignoring kinetic and potential effects. Liquid water enters at 15°C and leaves at 23°C, neglecting the change in pressure on the liquid side. On the other side, the refrigerant R-134a enters at 12 bar, 90°C and 150 kg/h, and the outlet condition is 12 bar, 28°C. The heat from the outer surface of the heat exchanger will be neglected. a) Determine the mass flow rate of the liquid water flow in kg/h. b) Determine the entropy production of the heat exchanger in kW/K.(THERMODYNAMICS)
A refrigeration cycle draws heat (Q C ) from the cold well at T C =280K, while the hot well at T H =320K dissipates heat to the source. Check whether the cycle works for each of the following conditions. Please specify. Determine if the cycle is reversible, irreversible, or impossible. a) Qc=1500 kJ, Wcycle =150 kJ. b) Qc = 1400 kJ, Qh =1600 kJ. c) Qh =1600 kJ, Wcycle = 400 kJ. d) COPsm = 5.
A single-pressure combined-cycle power plant consisting of a gas turbine, HRSG, and steam turbine plant. The gas turbine exhaust gas flow rate is 600 kg/s, temperature is 600°C, live steam condition is 70 bar/500°C, condenser pressure is 0.04 bar, and feedwater temperature is 140°C. Assuming a pinch point of 12 K for both high and low pressure, an exhaust gas specific heat of 1.05 kJ/(kg K), and an isentropic efficiency of the steam turbine of 0.9, calculate: (a) the rate of steam production in kg/s, (b) the stack gas temperature in °C, (c) the steam turbine power output in MW, and (d) the heat transfer rate in the HRSG in kJ/s.
For the NH3/H2O cycle the following relationship give the solution flow rate per unit refrigeration rate: WFS_A * X - WFS_G(X-1) = 1 where WFS_A = mass fraction of NH3 in solution form the absorber WFS_G = mass fraction of NH3 in solution from the generator X-1 =mass of solution from the generator per unit mass of refrigerant flow For large systems, a reasonable pressure drop between the evaporator and absorber is 1.5 psi Consider a large NH3/H2O plant operating per the schematic below: Known/given: i. Refrigeration load = 500 tons ii. Evaporator temperature (state point 10) = 41.1 F iii. Evaporator pressure (state point 10) = 75 psia iv. Absorber pressure (state point 11) = 73.5 psia (per rule of thumb above regarding pressure drop between the evaporator and absorber) v. Strong aqua solution temperature (state point 3) = 105 F vi. Condenser temperature (state point 8) = 100 F vii. Condenser and tower pressure (state point 7) = 211.9 psia viii. Concentration split, WFS_G - WFS_A =6%…
A Rankine Engine-Generator unit receives 27,000 kg/hr of steam at 1.2 MPa and 150°C and exhausts to a condenser temperature of 22 C. Brake steam rate is 4.74 kg/kW-hr, mechanical efficiency is 90 % and generator efficiency is 94 %. Determine: a) ideal cycle thermal efficiency, b) indicated engine efficiency, c) generator output (kW), d)the condition of turbine actual exhaust
A steam-powered power plant works on the basic Rankine cycle.shown in the figure. Likewise, some of its thermodynamic states are summarized in the attached table.Knowing that the work per unit mass delivered to the pump is 3W4 = 2480 (J/kg], determinein SI units the following: a) The specific volume of water in state 4.b) The associated work per unit mass, developed in the Curbina.c) The associated heat per unit mass released by the water in the condenser.d) The efficiency of the cycle
A cogeneration power plant operating in a thermodynamic cycle at steady state. Theplant provides electricity to a community at a rate of 80 MW. Of this, 70 MW isprovided to the community for water heating and the remainder is discarded to theenvironment without use. The electricity is valued at $0.08 per kWh. If the cyclethermal efficiency is 40 %, determine thei. rate energy is added by heat transfer, , in MWii. rate energy is discarded to the environment, in MWiii. value of the electricity generated, in $ per year
A power cycle operates between two thermal reservoirs at 300 K and 800 K. The working fluid of the cycle is air, which can be considered to be an ideal gas. Specific heats are not assumed to be constant. An inventor claims that for a heat input of 250 kJ, the net work from the cycle is 80 kJ. The work generating component in the cycle is a reversible, steady state turbine. The inlet pressure and temperature are 1000 kPa and 600 K and the exit temperature is 550 K. The turbine receives 150 kJ/kg of heat from the high temperature reservoir and loses 10 kJ/kg of heat to the ambient at 298 K. (a) Prove whether or not the overall cycle is possible using second law arguments. (b) determine the work done by the turbine [kJ/kg]

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