7.58 Figure PZ.58 shows a gas turbine power plant using air as the working fluid. The accompanying table gives steady-stateoperating data. Air can be modeled as an ideal gas. Stray heat transfer and the effects of motion and gravity can be ignoredLet To 290 K, po = 100 kPa. Determine, each in kJ per kg of air flowing, (a) the net power developed, (b) the net exergyincrease of the air passing through the heat exchanger, (eg- e), and (c) a full exergy accounting based on the exergysupplied to the plant found in part (b). Comment.State p(kPa) T(K) h(kJ/kg) s° (kJ/kg K)1100 290 290.161.6680500 505 508.1722.22973 500 875 904.992.81704 100 635 643.932.4688a o is the variable appearing in Eq. 6.20a and Table A-22.Heat exchangerCompressorTurbineFIGURE P7.58

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Asked Sep 11, 2019
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7.58 Figure PZ.58 shows a gas turbine power plant using air as the working fluid. The accompanying table gives steady-state
operating data. Air can be modeled as an ideal gas. Stray heat transfer and the effects of motion and gravity can be ignored
Let To 290 K, po = 100 kPa. Determine, each in kJ per kg of air flowing, (a) the net power developed, (b) the net exergy
increase of the air passing through the heat exchanger, (eg- e), and (c) a full exergy accounting based on the exergy
supplied to the plant found in part (b). Comment.
State p(kPa) T(K) h(kJ/kg) s° (kJ/kg K)
1100 290 290.16
1.6680
500 505 508.17
2
2.2297
3 500 875 904.99
2.8170
4 100 635 643.93
2.4688
a o is the variable appearing in Eq. 6.20a and Table A-22.
Heat exchanger
Compressor
Turbine
FIGURE P7.58
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7.58 Figure PZ.58 shows a gas turbine power plant using air as the working fluid. The accompanying table gives steady-state operating data. Air can be modeled as an ideal gas. Stray heat transfer and the effects of motion and gravity can be ignored Let To 290 K, po = 100 kPa. Determine, each in kJ per kg of air flowing, (a) the net power developed, (b) the net exergy increase of the air passing through the heat exchanger, (eg- e), and (c) a full exergy accounting based on the exergy supplied to the plant found in part (b). Comment. State p(kPa) T(K) h(kJ/kg) s° (kJ/kg K) 1100 290 290.16 1.6680 500 505 508.17 2 2.2297 3 500 875 904.99 2.8170 4 100 635 643.93 2.4688 a o is the variable appearing in Eq. 6.20a and Table A-22. Heat exchanger Compressor Turbine FIGURE P7.58

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Expert Answer

Step 1

(a)

 

Since at the power plant both turbine and compressor are involved, write the expression for the net power developed in the plant.

net
(-) )
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net (-) )

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Step 2

Substitute suitable values.

net (904.99-643.93) kJ/kg - (508.17-290.16) kJ/kg
= 43.05 kJ/kg
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net (904.99-643.93) kJ/kg - (508.17-290.16) kJ/kg = 43.05 kJ/kg

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Step 3

(b)

 

Write the expression for net exergy increase f...

2 = (h -/)-v+g(Z; -Z,)-T,(5, -5,)
e-e(hh)+
2
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2 = (h -/)-v+g(Z; -Z,)-T,(5, -5,) e-e(hh)+ 2

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