Analysis of a sweet-smelling, neutral compound of carbon, hydrogen and oxygen produced the following results: %C = 54.5; %H = 9.1. 3. From its mass spectrum, the molecular ion had a mass/charge ratio of 88. Its infra-red spectrum showed a prominent peak at 1735 cm-. Figure 121 shows the NMR spectrum of the compound. Figure 121 absorption of energy

Analysis of a sweet-smelling, neutral compound of carbon, hydrogen and oxygen produced the following results: %C = 54.5; %H = 9.1. 3. From its mass spectrum, the molecular ion had a mass/charge ratio of 88. Its infra-red spectrum showed a prominent peak at 1735 cm-. Figure 121 shows the NMR spectrum of the compound. Figure 121 absorption of energy

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter14: Mass Spectrometry

Section: Chapter Questions

Problem 14.24P

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Analysis of a sweet-smelling, neutral compound of carbon, hydrogen and oxygen produced the following results: %C = 54.5; %H = 9.1. From its mass spectrum, the molecular ion had a mass/charge ratio of 88. Its infra-red spectrum showed a prominent peak at 1735 cm–1. Figure below shows the NMR spectrum of the compound. Suggest a structural Formula for this compound.
The base peak in the mass spectrum of 2,2,5,5-tetramethylhexane (molecular mass = 142) is at m/z = 57, which corresponds to a composition of C4H9. Suggest a structure for the fragment that accounts for this peak and offer a reason for why this fragment is so abundant.
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12. The mass spectrum of 2,2-dimethylpropane shows only a very weak molecular ion peak at m/z = 72. However, a large peak at m/z = 57 is seen. Suggest a possible structure of the fragment giving rise to this large peak and suggest a reason as to why this peak is so large. type answer
The NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 and are found in the accompanying file. The 1H are also listedbelow. Identify the name of compound 1 and Provide a full analysis of the NMR spectra for compound 1 with table showing peak name and assignment 1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).
What is the NMR Spectra for C6H10O2 and what is the chemical formula for the compund?
biphenyl has an absorbance maximum at 245 nm. Obtain the UV-Vis spectrum of biphenyl Which of the following solvents (toluene, methanol, hexane) would youuse for the task? Explain.
The molecular ion peak, M at m/z 124 and the relative abundance of M, M+1, and M+2 is 100%, 2.21%, and 99.86%. Determine all the possible chemical formulas based on the given information.
When measured in a 1-cm cell, an 8.50 x 10-5 M solution of species A exhibited absorbances of 0.129 and 0.764 at 475 and 700 nm, respectively. A 4.65 x 10-5 M solution of species B gave absorbances of 0.567 and 0.083 under the same circumstances. Calculate the concentrations of A and B in solutions that yielded the following absorbance data in a 1.25 cm cell : 0.502 at 475 nm and 0.912 at 700 nm. Pls answer need help.
6. A sample of an alum was analysed by atomic spectroscopy and gravimetrically to determine its structure. A 0.1000 g of the sample when treated with BaCl₂ produced 0.0984 g of a white solid after drying to constant weight. Another 0.1000 g sample of the alum when heated at 105°C for several hours produced a weight loss of 0.04558 g while the % of K in the sample was determined by atomic spectroscopy to be 8.240%. Use these results to work out a formula for the alum. [M,/ g mole¹: K 39.10; Al 26.98; BaSO, 233.39; SO² 96.06; H₂O 18.0148]