Analyze the following code: // Enter an integer Scanner input = new Scanner(System.in); int number = input.nextInt()B %3D if (number <= 0) System.out.println(number); O If number is zero, number is displayed. The if statement is wrong, because it does not have the else clause. O number entered from the input cannot be negative. O System.out.println(number); must be placed inside braces.

Analyze the following code: // Enter an integer Scanner input = new Scanner(System.in); int number = input.nextInt()B %3D if (number <= 0) System.out.println(number); O If number is zero, number is displayed. The if statement is wrong, because it does not have the else clause. O number entered from the input cannot be negative. O System.out.println(number); must be placed inside braces.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Computer Science Short Answer Write a program that uses the Scanner to ask the user for an integer, but forces the user to repeatedly re-enter the number until they enter a negative value. Then if the number is odd, print it out. Otherwise, check if the number is less than -10 and if so, print it out twice. For example: 4 you would be forced to re-enter -3 is printed once -8 is not printed -13 is printed once -40 is printed twice.
user_input input () while user input != 'end': try: #Possible ValueError divisor = int (user_input) if divisor < 0: = except: else: # Possible ZeroDivisionError print (20 // divisor, end=' ') except ValueError: print ('v', end='') except ZeroDivisionError: print ('z', end=' ') # Possible NameError # compute () is not defined print (compute (divisor), end=' ') print ('x', end=' ') print ('OK') Type the program's output user_input input () # // truncates to an integer 2 Input five 2 0 -8 end Output
The Upper bound limit is 90, lower bound limit is -100. If a value is inputted (not through user but through a test) if the value is greater than 90 return 90. If the value is lower than -100 return -100. If the value is 0 return -1000.
Print "user_num1 is negative." if user_num1 is less than 0. End with newline. Assign user_num2 with 1 if user_num2 is greater than 12. Otherwise, print "user_num2 is less than or equal to 12.". End with newline. My code: user_num1 = int(input())user_num2 = int(input()) if user_num1 < 0: print("user_num1 is negative.") if user_num2 > 12: user_num2 == 1 else: print("user_num2 is less than or equal to 12.") print('user_num2 is', user_num2) When the input is 0 and 13 my output for user_num2 is 13 and it should be 1. I don't know what I'm doing wrong.
Binary-Decimal / Decimal Binary . Between 0 and 255 a number will be decided randomly by computer. Then asks to user 3 times a random digit of binary value of the that number. If user enters wrong number for a digit program will select another random number and ask random times random digit. Every time user enters input will be counted as one hour in that planet. For example: Computer selected number as 163 ( Which is 10100011) What is the digit 2 (question 1/3) :User enter 1 CorrectWhat is the digit 4 (question 2/3) : User enter 0 CorrectWhat is the digit 7 (question 3/3) : User enter 0 CorrectUser finished the quest with 3 input .
The term "Pre-test" means that The loop is tested after the body statements are run. OThe loop is tested after the loop is run through for the first time OThe loop will be tested before the statements to be repeated are executed, even once. OThe loop will be tested before the next iteration (after the first)
Slide Type Slide Exercise # 3: Write a program that first asks the user to type today's price for one dollar in Japanese yen, then reads US dollar values and converts each to yen. Use 0 as a sentinel. • The following are sample runs of the program. Slide Type Enter today's price in yens for 1 $: 105.69 Enter amount in dollars to convert: (0 to quit) 200 200.00 dollars = 21138.00 yens Enter amount in dollars to convert: (0 to quit) 500 500.00 dollars = 52845.00 yens Enter amount in dollars to convert: (0 to quit) 100 100.00 dollars = 10569.00 yens Enter amount in dollars to convert: (0 to quit) e Slide Type Enter today's price in yens for 1 $: 105.6 Enter amount in dollars to convert: (0 to quit) e Slide Type # Exercises # 3 Source Code
The following loop displays _____. for (int i = 1; i <= 10; i+=2) { System.out.print(i + " "); i++; } a)1 2 3 4 5 6 7 8 9 b)1 2 3 4 5 6 7 8 9 10 c)1 3 5 7 9 d)3 5 7 9 11
а. int GreaterThan(int no) { if (no > 10) printf("%d is greater than 10", no); else printf("%d is less than 10", no); }
Programming Language: Java Direction: Write a program to determine the number of PASSED and FAILED out of 15 inputted names with the corresponding grade. Restrict the inputted grade for each name in the range of 50 to 100, in which 75 is the passing grade. If the inputted grade is not on the range, the program will remind the user of a message for the accepted range for the grade and allows the user to re-enter a grade. NOTE: MUST ADD COMMENTS
In the switch statement, we can use int type only for the control variables that are being tested in the loop condition. True False
Find the error in the following code: The following code was intended for inputting scores for 20 students. If an invalid value was input, the program should keep reminding the user to re-input till a valid value is input. //Create Scanner object Scanner myScanner = new Scanner(System.in); //Declare variables final int studentNumber = 20; int scores[] = new int[studentNumber]; //Use while loop to allow user keep trying till valid input while(true) { for(int i=0; i<scores.length; i++) { System.out.println("Score for student "+(i+1)); scores[i] = myScanner.nextInt(); if( 100 >= scores[i]>=0){ break; } //Otherwise continue the loop } // end for }//end while