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Answer the following: Write the equilibrium constant expression of the following reversible reaction. Use the given K to predict the direction that the reaction favors in achieving equilibrium

Answer the following: Write the equilibrium constant expression of the following reversible reaction. Use the given K to predict the direction that the reaction favors in achieving equilibrium

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 9ALQ
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Answer the following: Write the equilibrium constant expression of the following reversible reaction. Use the given K to predict the direction that the reaction favors in achieving equilibrium
Write the equilibrium constant expression of the following reversible reactions. Use the given K to predict the direction that the reaction favors in achieving equilibrium. EQUILIBRIUM CONSTANT EQUILIBRIUM CONSTANT EXPRESSION REACTION FORWARD REACTION OR REVERSE REACTION 1. H+ Br 2HBr. 2. HC,H,OH +C,H,O 3. Al(OH) Al + 30H 4. 2NON+O 5. N+ 3H 2NH Kat 25 =2.0 x 10 Kat 25- 1.7x 10 Kat 25- 1.3 x 10 Kat 25 - 2.24 x 10" Kat 25 = 3.65 x 10
Transcribed Image Text:Write the equilibrium constant expression of the following reversible reactions. Use the given K to predict the direction that the reaction favors in achieving equilibrium. EQUILIBRIUM CONSTANT EQUILIBRIUM CONSTANT EXPRESSION REACTION FORWARD REACTION OR REVERSE REACTION 1. H+ Br 2HBr. 2. HC,H,OH +C,H,O 3. Al(OH) Al + 30H 4. 2NON+O 5. N+ 3H 2NH Kat 25 =2.0 x 10 Kat 25- 1.7x 10 Kat 25- 1.3 x 10 Kat 25 - 2.24 x 10" Kat 25 = 3.65 x 10
REACTION EQUILIBRIUM CONSTANT - 2HBrg) 1. Hze) + Brzie = 2HBr) 2. HC,H,Olea)=H°eg) 3. Al(OH)3 = Al*3 + 30Hag) Keg at 25 = 2.0 x 1019 Kegat 25 = 1.7 x 10s Keg at 25 = 1.3 x 1033 %3D 4. 2NOR= N2(9) + Ozig) Kegat 25 = 2.24 x 1030 (3) 5. Nze + 3H2= 2NH 3(9) Keg at 25 = 3.65 x 10% 2(g)
Transcribed Image Text:REACTION EQUILIBRIUM CONSTANT - 2HBrg) 1. Hze) + Brzie = 2HBr) 2. HC,H,Olea)=H°eg) 3. Al(OH)3 = Al*3 + 30Hag) Keg at 25 = 2.0 x 1019 Kegat 25 = 1.7 x 10s Keg at 25 = 1.3 x 1033 %3D 4. 2NOR= N2(9) + Ozig) Kegat 25 = 2.24 x 1030 (3) 5. Nze + 3H2= 2NH 3(9) Keg at 25 = 3.65 x 10% 2(g)
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