aram 10 20 30 40 50 cm

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter18: Refraction And Lenses
Section18.1: Refraction Of Light
Problem 9SSC
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A mass hanging from a vertical spring is somewhat more complicated than a mass attached to a horizontal spring because the gravitational force acts along the direction of motion. Therefore, the restoring force of the oscillations is not provided by the spring force alone, but by the net force resulting from both the spring force and the gravitational force. Ultimately, however, the physical quantities of motion (position, velocity, and acceleration) for a vertical mass on a spring exhibit the same oscillations as a horizontal mass on a spring.

A 100 g mass hangs from a vertical spring as shown in the picture. The measuring stick shows us the vertical y position of the bottom of the spring with the origin (y = 0) at the top of the spring. Note that the positive y direction is downward. The 100 g mass is at rest at the position shown (y = 50 cm). The dashed line in the picture (y = 30 cm) indicates the unstretched resting length of the spring. The mass is pulled down 6 cm, stretching the bottom of the spring to y = 56 cm, and then released so that it begins oscillating.
 



1. What are the equilibrium position and amplitude of the oscillations?
y =  ______ cm
A =  ______ cm

2. What is the spring constant?
k =  ______ N/cm

3. What is the force of the spring on the mass (magnitude and direction) at both the highest point of the oscillation (smallest y) and the lowest point of the oscillation (largest y)? If the force is zero, enter 0 for the magnitude and choose No direction.
Fspring (highest) =  _______ N,  --Select-- Down,Up, No direction (force is 0)
Fspring (lowest) = ________ N, --Select-- Down,Up, No direction (force is 0)

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Transcribed Image Text:aram 10 20 30 40 50 cm
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