Arrange the following in decreasing reactivity to NaI in acetone 1-bromopentane 2-bromopentane 2-bromo-2-methylpentane a. II, I, III b. I, II, III c. I, III, II d. III, II, I
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Arrange the following in decreasing reactivity to NaI in acetone
- 1-bromopentane
- 2-bromopentane
- 2-bromo-2-methylpentane
|
a. II, I, III |
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b. I, II, III |
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c. I, III, II |
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d. III, II, I |
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- handwritten please Complete reactions i. to iii. b) Provide a qualitative discussion regarding the thermodynamic stability of the products for the substitution reactions i, ii and iii. (Note all products have coordination number 6): i) [Mn(H2O)6]2+ + bpy → ii) [Mn(H2O)6]2+ + CO32- → iii) [Mn(H2O)6]2+ + 2NH3 + Qualitatively compare the equilibrium constants for i vs. ii, i vs. iii and ii vs. iii.Which analysis EPR or NMR is more appropriate for the composition of the palatable acid and vanadil complex. Please explain.In inorganic chemistry we learned about hard/soft acid/base. What is the best way to understand the difference between these terms? And using hard/soft acid/base arguments determine: 1.) rank of the order of reactivity of Pt2+ with NH3 and F- and Ph3P and why? 2.) does CO react more strongly with Fe2+ or Fe3+ and why?
- In the presence of 18-crown-6, potassium permanganate dissolves in benzene to give“purple benzene,” a useful reagent for oxidizing alkenes in an aprotic environment. Use adrawing of the complex to show why KMnO4 dissolves in benzene and why the reactivityof the permanganate ion is enhanced.In an experiment, triphenylmethanol is prepared using the Grignard reaction. Reaction of bromobenzene with magnesium in ether produces phenylmagnesium bromide. This Grignard reagent then reacts with methyl benzoate to produce the corresponding alkoxide. Reaction of the alkoxide with aqueous acid then produces the alcohol. Give a plausible, three dimensional structure for the complex RMgBr-2(C2H5)2O. How do you think the ether molecules are bonded to the Grignard reagent?Complete the balanced dissociation equation for the compound below in aqueous solution. If the compound does not dissociate, write NR after the reaction arrow. Be sure to include the proper phases for all species within the reaction. NiS(s)→
- TRUE OR FALSE: Because of chelate effect, the formation reaction of the complex tris(ethylenediamine)cobalt(III) has a smaller negative ΔGrxn and a larger positive ΔSrxn compared to the formation of hexaamminecobalt(III).Complete reactions i. to iii. b) Provide a qualitative discussion regarding the thermodynamic stability of the products for the substitution reactions i, ii and iii. (Note all products have coordination number 6): i) [Mn(H2O)6]2+ + bpy → ii) [Mn(H2O)6]2+ + CO32- → iii) [Mn(H2O)6]2+ + 2NH3 + Qualitatively compare the equilibrium constants for i vs. ii, i vs. iii and ii vs. iii.Describe main features of the evidence of M-CºC characterization and corresponding techniques of this complex (COCL(PPh3)2-III(CF3)2)...?
- Outline the mechanism showing both products formed for the reaction of ammonia (2 mole equivalent) with 1-bromobutane (1 mole equivalent).Provide details about the reaction workup. 4,4'-DIBROMOBIPHENYL [Biphenyl, 4,4'-dibromo-] Submitted by Robert E. Buckles and Norris G. Wheeler1. Checked by R. S. Schreiber, Wm. Bradley Reid, Jr., and Robert W. Jackson. 1. Procedure In a 15-cm. evaporating dish is placed 15.4 g. (0.10 mole) of finely powdered biphenyl (Note 1). The dish is set on a porcelain rack in a 30-cm. desiccator with a 10-cm. evaporating dish under the rack containing 39 g. (12 ml., 0.24 mole) of bromine. The desiccator is closed, but a very small opening is provided for the escape of hydrogen bromide (Note 2). The biphenyl is left in contact with the bromine vapor for 8 hours (or overnight). The orange solid is then removed from the desiccator and allowed to stand in the air under a hood for at least 4 hours (Note 3). At this point, the product weighs about 30 g. and has a melting point in the neighborhood of 152°. The crude 4,4'-dibromobiphenyl is dissolved in 75 ml. of benzene, filtered, and cooled to 15°.…Why cis-Ru(II)Cl2(DMSO)4 reacts with pyridine, et cetera, to give substitution of the DMSO but not the chloride ligands, but trans-Ru(II)Cl2(py)4 react with suitable Na+ and K+ salts in aqueous pyridine to afford chloride-substituted derivatives. write the reactions equations.