ArrayList list = new ArrayList(); for (int i = 1; i <= 10; i++) { list.add(10 * i); } for (int i = 0; i < list.size(); i++) { list.remove(i); }
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Java
Copy the following code to a java file and explain in the comment what is the output and why.
1- ArrayList list = new ArrayList();
for (int i = 1; i <= 10; i++) {
list.add(10 * i);
}
for (int i = 0; i < list.size(); i++) {
list.remove(i);
}
System.out.println(list); // what is the expected output?
2- ArrayList list = new ArrayList();
for (int i = 1; i <= 10; i++) {
list.add(10 * i);
}
int size = list.size();
for (int i = 0; i < size; i++) {
list.add(i, 42);
}
System.out.println(list); // what is the expected output?
Step by step
Solved in 3 steps
- The implementation of a queue in an array, as given in this chapter, uses the variable count to determine whether the queue is empty or full. You can also use the variable count to return the number of elements in the queue. On the other hand, class linkedQueueType does not use such a variable to keep track of the number of elements in the queue. Redefine the class linkedQueueType by adding the variable count to keep track of the number of elements in the queue. Modify the definitions of the functions addQueue and deleteQueue as necessary. Add the function queueCount to return the number of elements in the queue. Also, write a program to test various operations of the class you defined.Using the picture, use Java to design and implement the class PascalTriangle that will generate a Pascal Triangle from a given number of rows. Represent each row in a triangle as a list and the entire triangle as a list of these lists, implement the class ArrayList for these lists.using arrays or Arraylist in Java language Write the method filterBySize().* * Given an ArrayList of String, return a new list where only * strings of the given length are retained.* * Examples:* filterBySize(["a", "bb", "b", "ccc"], 1) returns ["a", "b"]* filterBySize(["a", "bb", "b", "ccc"], 3) returns ["ccc"]* filterBySize(["a", "bb", "b", "ccc"], 4) returns []* * @param list the list of Strings to process.* @param n the size of words to retain.* @return a new list of words with the indicated size retained.
- You are given a non-negative number in the form of list elements. For example, the number 123 would be provided as [1, 2, 3]. Add one to the number and return the output in the form of a new list. import java.util.ArrayList;public class AddOneToArrayList{public static ArrayList<Integer> solution(ArrayList<Integer> list){// ↓↓↓↓ your code goes here ↓↓↓↓return new ArrayList<>();}}import java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…in java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…
- Write Java statements to add the integers 1001, 1100, and 1110 to the resulting ArrayList import java.util.*;public class test { public static void main(String[] args) { //Set n =25 int n = 25; //ArrayList of Integer type with size,n=25 ArrayList<Integer> list = new ArrayList<Integer>(n); for(int i = 0;i<n;i++){ //Assign -1 to all the objects of the array list,list list.add(-1); } //Add 1001 to the list list.add(1001); //Add 1100 to the list list.add(1100); //Add 1110 to the list list.add(1110); //Reset the number of elements in the list becomes 28 //Use size() method to get the size of the list. n=list.size(); //for loop to print the list for(int i = 0;i<n;i++){ System.out.print(list.get(i) + " "); } }} 1. Write the Java statement to display the size of the resulting ArrayList from above.Suppose list is an array of 6 components of the type int. What is stored in the array list after the following Java code executes? list[0] = 5; for (int i = 1; i < 6; i++) { list[i] = i * i + 5; if ( i > 2) list[i] = 2 * list[i] – list[i– 1]; }Fix the following method printEvenIndex so that it will print out the Integers at even indices of the passed-in ArrayList list. import java.util.*; public class Test1 { public static void printEvenIndex(ArrayList<Integer> list) { for (int i) { if (i % 2 == 1) { System.out.print(list.get(i) + ", "); } } } public static void main(String[] args) { //instantiate ArrayList and fill with Integers ArrayList<Integer> values = new ArrayList<Integer>(); int[] nums = {1, 5, 7, 9, -2, 3, 2}; for (int i = 0; i < nums.length; i ++) { values.add(nums[i]); } System.out.println("Expected Result:\t 1, 7, -2, 2,"); System.out.print("Your Result:\t\t "); printEvenIndex(values); } }
- In java, Implement a method that removes all duplicates. Keep the first instance of the element but remove all subsequent duplicate elements.public void removeDuplicates() see the picture for the right output. Given files: Demo6.java public class Demo6 { public static void main(String[] args) { MyLinkedList<String> list = new MyLinkedList<>(); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); for (int x = 0; x < list.size(); x += 1 + x/3) { System.out.println("Removing element at index: " + x); list.remove(x); } System.out.println("Result"); System.out.println(list); System.out.println("Shuffling"); list.shuffle(7777); System.out.println(list); System.out.println("Removing duplicates (keeping first instance)"); list.removeDuplicates(); System.out.println(list); }} TestBench.java import java.util.AbstractList; public class TestBench { public static…PROBLEM STATEMENT: Return a sublist of a given list from the range of the two integerinputs from, to. public class FindSublistFromRange{public static ArrayList<Integer> solution(ArrayList<Integer> elms, int from, int to){// ↓↓↓↓ your code goes here ↓↓↓↓return new ArrayList<>();} Can you help me with this question The language is Java Please use the code i provided above to answer this questionUsing JAVA, write a method that modifies an ArrayList<String>, moving all strings starting with an uppercase letter to the front, without otherwise changing the order of the elements. Write a test program to demonstrate the correct operation of the method.