Assuming a pure-breeding P generation, what ratio would you expect in the F2 generation if a mutant phenotype is inherited in an autosomal recessive fashion? (remember, F1 are intercrossed) O 3 wildtype:1 mutant O 75% mutant and 25% wildtype O 1 mutant female: 1 mutant male : 1 wildtype female : 1 wildtype male O 50% mutant: 25% wildtype : 25% mutant, wildtype O All F2 will be mutant
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- The lubber grasshopper is a very large grasshopper, and is black with red and yellow stripes. Assume that red stripes are expressed from the homozygous RR genotype, yellow stripes the homozygous R’R’ genotype, and both from the heterozygous genotype RR’. What will be the phenotypic ratio of the F1 generation resulting from a cross of two grasshoppers, both with red and yellow stripes? What type of of inheritance is this?You have a Drosophila line that is homozygous for autosomal recessive alleles a, b, and c, linked in that order. Youcross females of this line with males homozygous for thecorresponding wild-type alleles. You then cross the F1 heterozygous males with their heterozygous sisters. You obtain the following F2 phenotypes (where letters denoterecessive phenotypes and pluses denote wild-type phenotypes): 1364 + + +, 365 a b c, 87 a b +, 84 + + c,47 a + +, 44 + b c, 5 a + c, and 4 + b +.a. What is the recombinant frequency between a andb? Between b and c? (Remember, there is no crossingover in Drosophila males.)b. What is the coefficient of coincidence?You believe that the gene you're investigating, eyes absent, is an autosomal recessive mutant allele F7 ge in Drosophila. You set up a cross between a true-breeding mutant male and a true-breeding wildtype female to obtain the F1 generation. You then cross the F1 flies. In the F2 offspring, you observe the following: 237 wild-type males 180 wild-type females 70 mutant males 83 mutant females Based on these findings, is the mutant allele autosomal recessive? How do you know?
- F1 result Wild-type Mutant P: Wild type female x mutant male 0 258 P: wild type male x mutant female 0 193 F2 result Wild type Mutant F1 male x F1 female 268 205 what is the most likely mode of inheritance? 1. What is the Chi-square value for F2?In rabbits, the coat color black dominant (B) over brown (b). Short hair is dominant (S) over long (s). In a cross between a homozygous black short-haired male and a brown homozygous long-haired female, what would be the ratios for genotype and phenotype of the F1 generation?In mice, albinism (g) is recessive to grey coat colour (G). A grey mouse mated with an albino mouse. Over the course of several months, 38 pups were born. Out of 38 pups, 17 had a grey coat, and 21 were albino. Theoretically, what is the expected result from the parental cross of a grey mouse and an albino mouse, and why does the expected result not match the result stated in the information given above? a. Theoretically, there should be a 3:1 ratio of grey mice to albino mice, or 29 grey coat mice and 9 albino mice. With more litters, the actual results would match the expected results more closely. b. Theoretically, there should be a 1:1 ratio of grey mice to albino mice, or 19 grey coat mice and 19 albino mice. With more litters, the actual results would match the expected results more closely. c. Theoretically, 100% of the mice should have grey coats so all 38 offspring should have grey coats. There was an experimental error that can account for the deviation. d.…
- A rooster with a particular comb morphology calledwalnut was crossed to a hen with a type of comb morphology known as single. The F1 progeny all had walnut combs. When F1 males and females were crossedto each other, 93 walnut and 11 single combs wereseen among the F2 progeny, but there were also29 birds with a new kind of comb called rose and32 birds with another new comb type called pea.a. Explain how comb morphology is inherited.b. What progeny would result from crossing a homozygous rose-combed hen with a homozygouspea-combed rooster? What phenotypes and ratioswould be seen in the F2 progeny?c. A particular walnut rooster was crossed to a peahen, and the progeny consisted of 12 walnut,11 pea, 3 rose, and 4 single chickens. What are thelikely genotypes of the parents?d. A different walnut rooster was crossed to a rosehen, and all the progeny were walnut. What are thepossible genotypes of the parents?When a white guinea pig is crossed to a yellow guinea pig, all the progeny are cream-colored. From a cross of two such F1’s, the F2 showed 32 white, 66 cream, and 30 yellow guinea pigs. How is this trait inherited? _______________ Identify the genotype of the white guinea pig. ________ Identify the genotype of the yellow guinea pig. ________ Identify the genotype of the cream-colored guinea pig. ________ Identify the genotypes and the corresponding phenotypes of the F2 progeny. Give the genotypic ratio. __________________ Give the phenotypic ratio. ___________________Three genes in fruit flies affect a particular trait, and at least one dominant allele of each gene is necessary to get a wild-type phenotype. a. What phenotypic ratio would you predict among the progeny if you crossed triply heterozygous flies? b. You cross a particular wild-type male in succession with three tester strains. In the cross with one tester strain (AA bb cc), only 1/4 of the progeny are wild type. In the crosses involving the other two tester strains (aa BB cc and aa bb CC), half of the progeny are wild type. What is the genotype of the wild-type male? (Pls help asap!!)
- In mice, albinism (g) is recessive to grey coat colour (G). A grey mouse mated with an albino mouse. Over the course of several months, 38 pups were born. Out of 38 pups, 17 had a grey coat, and 21 were albino. Theoretically, what is the expected result from the parental cross of a grey mouse and an albino mouse, and why does the expected result not match the result stated in the information given above? Select one: a. Theoretically, there should be a 3:1 ratio of grey mice to albino mice, or 29 grey coat mice and 9 albino mice. With more litters, the actual results would match the expected results more closely. b. Theoretically, there should be a 1:1 ratio of grey mice to albino mice, or 19 grey coat mice and 19 albino mice. With more litters, the actual results would match the expected results more closely. c. Theoretically, 100% of the mice should have grey coats so all 38 offspring should have grey coats. There was an experimental error that can account for the deviation. d.…In roses, purple flower color is determined by the dominant P allele, while pphomozygotes are white. The presence of long stems is determined by the dominant S allele, while ss homozygotes have short stems. Both mutations are completely penetrant. A test cross was performed between a rose plant of unknown genotype with a white flowered, short stemmed rose plant (pp ss) and the following 200 progeny plants were obtained: 84 white flowers, long stems 16 purple flowers, long stems 82 purple flowers, short stems 18 white flowers, short stems Select two statements below that are TRUE. options: The P and S genes independently assort during meiosis. The map distance between P and S is 17 cM. The genotype of the progeny plants with purple flowers and short stems is PP ss. The map distance between P and S is 83 cM. The homologs in the plant with…Color blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?