Assuming an efficiency of 32.70%,32.70%, calculate the actual yield of magnesium nitrate formed from 145.4 g145.4 g of magnesium and excess copper(II) nitrate. Mg+Cu(NO3)2⟶Mg(NO3)2+Cu

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Assuming an efficiency of 32.70%,32.70%, calculate the actual yield of magnesium nitrate formed from 145.4 g145.4 g of magnesium and excess copper(II) nitrate.

Mg+Cu(NO3)2⟶Mg(NO3)2+Cu

 

Expert Solution
Step 1

Given for the following Reaction, efficiency is 32.70% -

Mg+Cu(NO3)2⟶Mg(NO3)2+Cu

 

Here , the Atomic mass/ molar mass of Different elements and compounds are -

Mg - 24.305 g/mol

Cu(NO3)2 - 187.56 g/mol

Mg(NO3)2 - 148.32 g/mol

Cu - 63.546 g/mol

 

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