Question

Asked Sep 14, 2019

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Assuming that the Earth has a uniform density p= 5540.0 kg/m^{3}, what is the value of the gravitational acceleration at a distance d= 4600 km from the earth's center?

Step 1

**Given information:**

Density of earth (p) = 5540.0 kg/m^{3}

Acceleration due to gravity at radius of (R) = 4600 km = 4600 × 10^{3 }m

Acceleration due to gravity (g) =?

Step 2

Let us consider a unit mass at the given radius of earth i.e. m = 1kg.

Let the mass of earth up to the given radius be (M), we can find M by:

M = D × V (Where “V” volume of the earth till the given radius)

But,

Step 3

According to newton law of gravitation the force be...

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